Question

the average number of phone inquiries per day at the poison control center is 4 find the probability it will receive 5 calls on a given day

Answer 1

Assuming a Poisson Distribution then probability it receives "k" calls is:
$P(x=k) = \frac{\lambda^k e^{-\lambda}}{k!}$
where $\lambda = 4, k =5$

Answer 2

Answer: The probability it will receive 5 calls on a given that is 0.15.

Step-by-step explanation:

Since we have given that

The average number of phone inquires per day at the poison control centre = 4

So, λ = 4

Number of calls received on a given day = 5

so, k = 5

We will use "Poisson Distribution" to find the probability that it will receive 5 calls on a given day.

So, it will be written as

$P(X=k)=\dfrac{\lambda^k.e^{-\lambda}}{k!}\\\\P(X=5)=\dfrac{4^5\times e^{-4}}{5!}\\\\P(X=5)=0.15$

Hence, the probability it will receive 5 calls on a given that is 0.15.