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Keith_Richards [23]
3 years ago
13

What's 10x-12y+8+12y equal?

Mathematics
2 answers:
BartSMP [9]3 years ago
7 0


Or if your simplifying


10x-12y+8+12y=

Simplifying 10x + -12y + 8 + 12y = 0

Reorder the terms: 8 + 10x + -12y + 12y = 0

Combine like terms: -12y + 12y = 0 8 + 10x + 0 = 0 8 + 10x = 0

Solving 8 + 10x = 0

Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-8' to each side of the equation.

8 + -8 + 10x = 0 + -8

Combine like terms: 8 + -8 = 0 0 + 10x = 0 + -8 10x = 0 + -8

Combine like terms: 0 + -8 = -8 10x = -8

Divide each side by '10'. x = -0.8 Simplifying x = -0.8

10x-12y+8+12y

Simplifying 10x + -12y + 8 + 12y

Reorder the terms: 8 + 10x + -12y + 12y

<span>Combine like terms: -12y + 12y = 0 8 + 10x + 0 8 + 10x
</span>

kakasveta [241]3 years ago
5 0
-12+12=0
10x+8 would be your answer
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Step-by-step explanation:

In 65 oz there are 4.0625 lb.

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Answer:

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Step-by-step explanation:

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<u></u>

P (Not the square) :

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2 years ago
Shade in some or all of the grids to show that 2 ones is the same as 20 tenths
scZoUnD [109]
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3 years ago
A 4-lb. force acting in the direction of (vector) 4,-2 moves an object just over 7ft from point (0,4) to (5,-1). Find the work d
Tcecarenko [31]

To solve this problem, we have to find the net displacement and the net force and the multiply the dot product together and get the work done.

The work done on moving the object is 27ft*lbs

<h3>Work done in moving the object from point A to point B</h3>

To find the work done on this object, let's find the net force on the object.

Data;

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  • direction = 4, -2
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  • direction = (0, 4) to (5,1)

The unit vector of the force is

\sqrt{4^2 +(-2)^2} =\sqrt{16 + 4} = \sqrt{20}

\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} }

The net force acting on the object is

F = 4(\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} })\\F= (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } )

The displacement on the object is 7ft through (0,4) to (5, -1)

The unit vector on displacement is

\sqrt{5^2 + (-1-4)^2} = \sqrt{25+25} = \sqrt{50}

\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }

The net displacement will be

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The work done will be F.d

w = f. d \\

w = (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } ) * \frac{35}{\sqrt{50} }, \frac{-35}{50}\\w = 17.71+ 8.854\\w = 26.567 = 27ft*lbs

The work done on moving the object is 27ft*lbs

Learn more on work done on an object here;

brainly.com/question/26152883

#SPJ1

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