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Answer:
a) the probability that this whole shipment will be accepted is 0.8731
b) Almost all shipments (87.31% of the shipments) would be accepted
Step-by-step explanation:
a) Given that:
p = 1% = 0.01
n = 48
Binomial probability states that
Addition rule for mutually exclusive events is:
P(A or B) = P(A) + P(B)
To get the probability that this whole shipment will be accepted we evaluate at x = 0, 1, 2
Using addition rule:
P(X ≤ 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.6173 + 0.1848 + 0.071 = 0.8731
the probability that this whole shipment will be accepted is 0.8731
b) Almost all shipments (87.31% of the shipments) would be accepted