A company that produces ribbon has found that the marginal cost of producing x yards of fancy ribbon is given by Upper C prime (
x )equalsnegative 0.00001 x squared minus 0.02 x plus 58 for x less than or equals 1600, where Upper C prime (x )is in cents. Approximate the total cost of manufacturing 1600 yards of ribbon, using 5 subintervals over [0 comma 1600 ]and the left endpoint of each subinterval.
1 answer:
Answer:
$624.90
Step-by-step explanation:
The total cost is the integral of the marginal cost. Here, you're asked to approximate that integral using 5 equal-width rectangles. The area of each rectangle is the product of its height and width. The height is given by the function value at the left end of the interval.
The table shows the function values at the left end of each of the 5 intervals. The intervals have width 1600/5 = 320. The total estimated cost is the sum of products of 320 and each of the table values. (Of course, 320 can be factored out of the sum to make the math easier.)
The estimated cost is ...
320(58 + 50.576 + 41.104 + 29.584 +16.016) = 62,489.6 . . . cents
≈ $624.90 . . . . cost of manufacturing 1600 yards of fancy ribbon
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Let the amount invested with 5% interest be x
Therefore, the amount invested with 6% interest will be (6000-x)
It is given that the total interest earned yearly is $337.5. Thus, the equation of interest will be:
Multiplying both sides by 100 we get:
Subtracting both sides by 36000 we get:
Thus, the amount invested at 5% is $2250
Therefore, the amount invested at 6% will be $(6000-2250)=$3750
Answer:
Answer below
Step-by-step explanation:
1/8 is correct
in pic
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(Hope this helps can I pls have brainlist (crown)☺️)
