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lapo4ka [179]
3 years ago
5

There are 2 brown marbles, 3 black marbles, and 4 gold marbles in a bag. What is the probability of drawing 2 brown marbles if t

he first is replaced after it is drawn?
Mathematics
1 answer:
prohojiy [21]3 years ago
5 0

Answer:

.049 (2sf)

Step-by-step explanation:

\frac{2}{9}  \times  \frac{2}{9}  = 0.4938

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What is the area of a rectangle if it is 1/2 of a meter long and 3/8 of a meter wide?
Sonbull [250]

Answer:

Area equals to 3/16

Step-by-step explanation:

You can compute this with the easiest way,that is with formula

Area=LENGTH×WIDTH

So,1/2 × 3/8=3/16

5 0
3 years ago
Solve the inequality 7(x + 4) &gt; 0.<br> a.x -4<br> c.x 4
sesenic [268]
Solve your inequality step-by-step.

7(x+4)>0

Simplify both sides of the inequality.

7x+28>0

Subtract 28 from both sides
.
7x+28−28>0−28

7x>−28

Divide both sides by 7.

7x/7 > −28/7

x > −4

5 0
3 years ago
Read 2 more answers
Draw a number line that includes both positive and negative integers from +5 to -5.
aleksandrvk [35]

Answer:

5 4 3 2 1 0 -1 -2 -3 -4 -5

Step-by-step explanation:

6 0
3 years ago
In ΔUVW, w = 9 cm, v = 2.2 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.
Alja [10]

Complete Question

In ΔUVW, w = 9 cm, v = 22 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.

Answer:

16.5°

Step-by-step explanation:

In ΔUVW, w = 9 cm, v = 22 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.

We solve using Sine rule formula

a/sin A = b/sin B

We are solving for angle W

∠V=136°

Hence:

22 /sin 136 = 9 /sin W

Cross Multiply

22 × sin W = sin 136 × 9

sin W = sin 136 × 9/22

W = arc sin [sin 136 × 9/2.2]

W = 16.50975°

W = 16.5°

3 0
3 years ago
a group of astronauts launched a model rocket from a platform. Its flight path is modeled by h= -4t^2+24t+13 where h is the heig
Eddi Din [679]

Answer:

6.5 seconds

Step-by-step explanation:

Keep in mind that when h=0, this is the same height for both when the model rocket takes off and lands, so when the rocket lands, time is positive. Thus:

h=-4t^2+24t+13\\\\0=-4t^2+24t+13\\\\t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\ \\t=\frac{-24\pm\sqrt{24^2-4(-4)(13)}}{2(-4)}\\ \\t=\frac{-24\pm\sqrt{576+208}}{-8}\\\\t=\frac{-24\pm\sqrt{576+208}}{-8}\\\\t=\frac{-24\pm\sqrt{784}}{-8}\\\\t=\frac{-24\pm28}{-8}\\\\t=\frac{-24-28}{-8}\\ \\t=\frac{-52}{-8}\\ \\t=\frac{52}{8}\\\\t=6.5

So, the amount of seconds that the model rocket stayed above the ground since it left the platform is 6.5 seconds

5 0
2 years ago
Read 2 more answers
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