Answer:
K'= (-1,-1)
J'= (-1,-5)
L'= (0,-3)
Step-by-step explanation:
What you do here is, input the (x,y) coordinates into the translation.
For example, the original point K is (-3,5). Insert this into the translation.
(-3,5) → (-3+2, 5-8) = (-1,-3)
Repeat this for the next coordinates of L and J.
J= (-3,3)
(-3,3) → (-3+2, 3-8) = (-1,-5)
L= (-2, 5)
(-2, 5) → (-2+2, 5-8) = (0,-3)
Answer:
rating from tallest to shortest:
1. charles
2.maria
3. su-lyn
Step-by-step explanation:
The midpoint of the segment:
(4, 7)
x=4 y= -7
The domain is the x-axis and the range is the y-axis.
To find the domain, you measure or count the widest part of this oval horizontally. So that is 3 units to the right of 0 and 3 units to the left of 0. I counted it exactly on the axis because that is the widest part of the oval.
To find the range, you again count or measure the widest part of the oval vertically. So that is 4 units above 0 and 4 units below 0.
<u>Final Answer</u>
D: -3 ≤ x ≤ 3
R: -4 ≤ x ≤4
Answer:
x=5
Step-by-step explanation:
I was working on this problem also.
Maybe my version will help, too.
You need to sketch f given the information you have.
f'(x) is approximately a a cubic polynomial which means f will look like a quartic (think W)
f slopes down (negative slope) to x=2 and then slopes down again...this is a horizontal tangent.
f then slopes down to to x=5 where is has a minimum and then slopes up.
if im not wrong
