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S_A_V [24]
4 years ago
13

How can foil be used in the medical field?

Mathematics
2 answers:
3241004551 [841]4 years ago
6 0
Many medicines are packed in aluminum foil.
-Thepopularoneha
brilliants [131]4 years ago
6 0
Hola hola 123 nc por q





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What are the first and last deciles of the standard Normal distribution?
aliya0001 [1]

My best Guess is

1.282 for upper . , -1.282 for lower.

Hope this Helps

-Dante

5 0
3 years ago
Which is greater 7500,000 m or 750 km
marta [7]

Step-by-step explanation:

both are equal

pls Mark brainliest

5 0
3 years ago
478000000000 in scientific notation
Svetllana [295]

Answer:

4.78 x 10^11

Here is the answer to your problem

4 0
3 years ago
Read 2 more answers
What is the value of x which proves that the runways are parallel? What is the measure of the larger angle?
makkiz [27]

Answer:

118°

Step-by-step explanation:

When two parallel lines are cut by a tranversal, then the exterior angles are supplimentary and the corresponding angles are congruent.

Therefore the angle above (15x - 17)° is also (5x + 17)° and the angle below (5x + 17)° is also (15x - 17)°.

Angles on a straight line adds up to 180°. So to know the measure of the larger angle we must both equations and equal it to 180° to find x in order to know the larger angle.

(5x + 17) + (15x - 17) = 180

5x + 15x + 17 - 17 = 180

20x = 180

20x/20 = 180/20

x = 9°

Nkw let's substitute x = 9 into the equations

5x + 17 =

5(9) + 17 =

= 62°

15x - 17 =

15(9) - 17 =

= 118°

Both equations should add up to be 180°.

Therefore the measure of the largest angle is 118°.

6 0
3 years ago
Find dy/dx if y =x^3+5x+2/x²-1
stiks02 [169]

<u>Differentiate using the Quotient Rule</u> –

\qquad\pink{\twoheadrightarrow \sf \dfrac{d}{dx} \bigg[\dfrac{f(x)}{g(x)} \bigg]= \dfrac{ g(x)\:\dfrac{d}{dx}\bigg[f(x)\bigg] -f(x)\dfrac{d}{dx}\:\bigg[g(x)\bigg]}{g(x)^2}}\\

According to the given question, we have –

  • f(x) = x^3+5x+2
  • g(x) = x^2-1

Let's solve it!

\qquad\green{\twoheadrightarrow \bf \dfrac{d}{dx}\bigg[ \dfrac{x^3+5x+2 }{x^2-1}\bigg]} \\

\qquad\twoheadrightarrow \sf \dfrac{(x^2-1) \dfrac{d}{dx}(x^3+5x+2) - ( x^3+5x+2)  \dfrac{d}{dx}(x^2-1)}{(x^2-1)^2 }\\

\qquad\twoheadrightarrow \sf \dfrac{(x^2-1)(3x^2+5)  -  ( x^3+5x+2) 2x}{(x^2-1)^2 }\\

\qquad\pink{\sf \because \dfrac{d}{dx} x^n = nx^{n-1} }\\

\qquad\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-(2x^4+10x^2+4x)}{(x^2-1)^2 }\\

\qquad\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-2x^4-10x^2-4x}{(x^2-1)^2 }\\

\qquad\green{\twoheadrightarrow \bf \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}\\

\qquad\pink{\therefore  \bf{\green{\underline{\underline{\dfrac{d}{dx} \dfrac{x^3+5x+2 }{x^2-1}}  =  \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}}}}\\\\

7 0
2 years ago
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