Answer:
H2S(g) + 2OH^-(aq) --------> S^2-(aq) + 2H2O(l)
Explanation:
We know that the net ionic equation shows the major reaction that occurs in the reaction system.
The molecular reaction equation is;
H2S(g) + 2NaOH(aq) ------> Na2S(aq) + 2H2O(l)
The complete ionic equation is;
H2S(g) + 2Na^+(aq) + 2OH^-(aq) --------> 2Na^+(aq) + S^2-(aq) + 2H2O(l)
Net ionic equation;
H2S(g) + 2OH^-(aq) --------> S^2-(aq) + 2H2O(l)
First we have to write balanced chemical equation:
CuSO₄.5H₂O + 4 NH₃ → [Cu(NH₃)₄]SO₄.H₂O + 4 H₂O
then calculate the molar mass of both CuSO₄.5H₂O and [Cu(NH₃)₄]SO₄.H₂O
MM CuSO₄.5H₂O = 249.612 g/mole
MM [Cu(NH₃)₄]SO₄.H₂O = 245.612 g/mole
from equation we see that:
1 mole CuSO₄.5H₂O ---gives ---> 1 mole [Cu(NH₃)₄]SO₄.H₂O
249.612 g ---gives ---> 245.612 g
? grams ---gives ---> 6 g complex
By cross multiplication we get that:
mass of CuSO₄.5H₂O required = 6.1 g
Answer:
a hypothetical gas whose molecules occupy negligible space and have no interactions, and which consequently obeys the gas laws exactly.
Explanation:
The mass in grams of one mole of a substance
Answer:
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