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MakcuM [25]
4 years ago
8

An alkene reacts with a strong protic acid to form a carbocation. However, an alkene will react with a halogen electrophile to f

orm a cyclic intermediate. Draw the curved arrow notation for both reactions.

Chemistry
1 answer:
MrRa [10]4 years ago
4 0

Answer:

Reaction mechanisms are shown below.

Explanation:

Alkene gives nucleophilic addition reaction with strong protic acid.

Proton from a strong protic acid ruptures pi-bond in alkene and makes a new C-H sigma bond and thereby produces a carbocation.

Lone pair on halogen atom first adds onto double bond by rupturing the pi-bond and this pi-bond electrons then simultaneously substitutes a halogen atom from diatomic molecule of halogen to produce a cyclic halogenium cation by forming two new C-X sigma bonds. (X=halogen atom)

Reaction mechanism has been shown below.

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Answer:

1.35\times 10^{-4} M was the concentration of the original solution.

Explanation:

M_1V_1=M_2V_2  (Dilution)

where,

M_1\text{ and }V_1 are molarity and volume of non diluted sample.

M_2\text{ and }V_2 are molarity and volume of diluted sample.

M_1=?

V_1=100.0 \mu L=0.1 mL

(1μL=0.001  mL)

M_2=6.41\times 10^{-6} M

V_2=2.00 mL + 100.0 \mu L=2.00 mL+0.1 mL=2.1 mL

Substituting all values :

M_1\times 0.1 mL=6.41\times 10^{-6} M\times 2.1 mL

M_1=\frac{6.41\times 10^{-6} M\times 2.1 mL}{0.1 mL}=1.35\times 10^{-4} M

1.35\times 10^{-4} M was the concentration of the original solution.

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