Question

Chandra wants to know how many moles are contained in 150.0g CCl4 what quantity of CCl4 should she use to make this conversion

Answer 1

Hey there!:

atomic mass :

C = 12.01070 amu

Cl = 35.4530 amu

Molar mass:

CCl4 = ( 1 * 12.01070 ) + ( 35.4530 *4 ) = 153.8227 g/mol


Therefore:

n = mass of solute / molar mass

n = 150.0 / 153.8227

n = 0.975 moles

hope this helps!

Answer 2

Answer:

Quantities of  CCl₄ =   153. 8227 g/mol

Explanation:

Thinking process:

Data:

The molar mass of CCl₄ is determined by adding the relative atomic masses in the compound. In this case:

Molar mass of chlorine, Cl = 35.453 amu (atomic mass units) or 35.453 g/mol

Molar mass of carbon, C = 12.0107 amu (lamu (atomic mass units) or  12.0107g/mol

Remember, 1 mole or carbon contains 12.0107 amu

The compouns contains: 1 carbion atom= 12.0107g/mol

                                          4 cholrine atoms = 4 * 35.453 g/mol

                                                                        = 141. 812 g/mol

Adding the atomic masses to get the total molecular mass of  CCl₄ = 12.0107 + 4 (35.453) = 153. 8227  g/mol

Butn number of moles in 150.0g CCl4  = $\frac{mass (g)}{molar mass (g/mol)}$

                                                                 = $\frac{150.0g}{153.8227g/mol}$

                                                                  =  0.975 moles

Therefore,  150.0g CCl4 makes 0.975 moles

The student used 153. 8227 g/mol  CCl₄ to make the conversion