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Ivanshal [37]
3 years ago
7

A 36 ft tree casts a 9 ft shadow at the same time a building casts a 15 ft shadow. How tall is the building?

Mathematics
1 answer:
mote1985 [20]3 years ago
7 0

Answer: The height of the tree is  27f t

Step-by-step explanation: We can set up a proportion comparing the height of each object to the length of the shadow.

h/s

h/15=18/10

Cross multiply

10.h= 18*15

10h=270

Use the multiplicative Inverse

10 h/ 10 = <em><u>270 /10 =27</u></em>

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Solve the equation sin theta = 0.3 to the nearest tenth. Use the restrictions 90degrees &lt; theta &lt; 180degrees.
Alexxandr [17]
We first do:
∅ = sin⁻¹(0.3)
∅ = 17.5°

To go into the second quadrant, we add 90°.
∅ = 17.5 + 90
= 107.5°
The answer is A.
5 0
4 years ago
Please help me answer <br> 70 is 160% of what?
Lina20 [59]
You are basically asking 160% of X = 70. 
1) 70 x 100 = 7000 (to turn the 70 into a %)
2) 7000 /160 = 43.75

You can reverse the equation to double check the answer. 
160% x 43.75 = 70
6 0
3 years ago
Read 2 more answers
Please help with this I am completely stuck on it
vaieri [72.5K]

Answer:

f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4

Step-by-step explanation:

Given:

The function, H(x)=\sqrt[3]{6x^{2}-4}

Solution 1:

Let f(x)=\sqrt[3]{x}

If f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}, then,

\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4

Solution 2:

Let f(x)=\sqrt[3]{x-4}. Then,

f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}

Similarly, there can be many solutions.

7 0
3 years ago
Four glasses of milk and 3 snack bars have a total of 74 carbohydrates (carbs), and 3 glasses of milk and 4 snack bars have a to
Korvikt [17]

Answer: Snack=10carbs. Milk=11carbs

Step-by-step explanation:

(4x11)+(3x10)= 74

(3x11)+(4x10)= 73

6 0
3 years ago
Convert 75 percent to a decimal
Crank

To convert to a decimal, divide by 100.

75 / 100 = .75

4 0
4 years ago
Read 2 more answers
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