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Reika [66]
3 years ago
8

Given the system of equations presented here:

Mathematics
1 answer:
Nata [24]3 years ago
6 0
2x + 4y = 14
4x + y = 20......multiply by -4
----------------
2x + 4y = 14
-16x - 4y = -80 (result of multiplying by -4)
---------------add
-14x = -66....as u can see, ur y's cancel out

so ur answer is : 1st answer choice <==

** and just so u know, u could have multiplied the 1st equation by -2, and it would have cancelled out ur x's
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Answer:

The maximum revenue is $1,20,125 that occurs when the unit price is $155.

Step-by-step explanation:

The revenue function is given as:

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First, we differentiate R(p) with respect to p, to get,

\dfrac{d(R(p))}{dp} = \dfrac{d(-5p^2 + 1550p)}{dp} = -10p + 1550

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\dfrac{d(R(p))}{dp} = 0\\\\-10p + 1550 = 0\\\\p = \dfrac{-1550}{-10} = 155

Again differentiation R(p), with respect to p, we get,

\dfrac{d^2(R(p))}{dp^2} = -10

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Thus by double derivative test, maxima occurs at p = 155 for R(p).

Thus, maximum revenue occurs when p = $155.

Maximum revenue

R(155) = -5(155)^2 + 1550(155) = 120125

Thus, maximum revenue is $120125 that occurs when the unit price is $155.

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Step-by-step explanation:

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