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2 years ago

Please asap ........................

Mathematics

1 answer:

mezya [45]2 years ago

4 0

If I’m correct then DE would be 15 and then AB would be 6.

Explanation: You would divide 24 by 8 and see by how much bigger triangle CDE is, and then for side DE you would multiply side BC by 3 and get 15, and then for side AB you would divide side DC by 3 and get 6! (I hope this helps)

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Given that (-5,-6) is on the graph of f(x), find the corresponding point for this function -1/3f(x).

masya89 [10]

<h3>Answer: (-5, 2)</h3>

Explanation:

We multiply the y coordinate by -1/3 because of the notation (-1/3)*f(x). Recall that y = f(x). The x coordinate stays the same.

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2 years ago

What is the width of a rectangular figure that has a 3 centimeter length less then twice the width and the perimeter is 24 centi

k0ka [10]

7 cm should be correct

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3 years ago

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Find the solution Y=-3x-5 y=9x+7 and show on graph

slava [35]

Answer:

(-1, -2)

Explanation:

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2 years ago

On a test, Shoshana got 65% or 23.4 of the items correct? How many items were on the test?

Marizza181 [45]

65 % ------------------ 23.4 items
100 % ----------------- x items
65 : 100 = 23.4 : x
65 x = 100 * 23.4
65 x = 2340
x = 2340 : 65
x = 36
Answer: there were 36 items on the test.

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2 years ago

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For a certain candy, 20% of the pieces are yellow, 15% are red, 20% are blue, 20% are green, and the rest are brown. a

OLEGan [10]

Answer:

Step-by-step explanation:

Based on the question we are given the percentages of each of the types of candies in the bag except for brown. Since the sum of all the percentages equals 75% and brown is the remaining percent then we can calculate that brown is (100-75 = 25%) 25% of the bag. Now we can show the probabilities of getting a certain type of candy by placing the percentages over the total percentage (100%).

Brown: $\frac{25}{100}$
Yellow or Blue: $\frac{20}{100} +\frac{20}{100} = \frac{40}{100}$ ....add the numerators

Not Green: $\frac{80}{100}$ .... since the sum of all the rest is 80%

Stiped: $\frac{25}{100}$ .... there are 0 striped candies.

Assuming the <u><em>ratios/percentages</em></u> of the candies stay the same having an infinite amount of candy will not affect the probabilities. That being said in order to calculate consecutive probability of getting 3 of a certain type in a row we have to multiply the probabilities together. This is calculated by multiplying the numerators with numerators and denominators with denominators.

3 Browns: $\frac{25*25*25}{100*100*100} = \frac{15,625}{1,000,000} = \frac{1.5625}{100}$

the 1st and 3rd are red while the middle is any. We multiply 15% * (total of all minus red which is 85%) * 15% like so.

$\frac{15*85*15}{100*100*100} = \frac{19,125}{1,000,000} = \frac{1.9125}{100}$

None are Yellow: multiply the percent of all minus yellow three times.

$\frac{80*80*80}{100*100*100} = \frac{512,000}{1,000,000} = \frac{51.2}{100}$

At least 1 green: multiply the percent of green by 100% twice, since the other two can by any

$\frac{20*100*100}{100*100*100} = \frac{200,000}{1,000,000} = \frac{20}{100}$

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2 years ago