Hi there! A = 78
A + 44 = B
We can plug in the values of A and B into the equation. We then get an equation with only one variable (x), which we can solve.
1x + 76 + 44 = - 6x + 134
Collect terms.
1x + 120 = - 6x + 134
Add 6x to both sides.
7x + 120 = 134
Subtract 120 from both sides
7x = 14
Divide both sides by 7
x = 14 / 7 = 2
A = 1x + 76
Now plug in the value of x we just found
A = 2 + 76 = 78
Answer:
11
Step-by-step explanation:
AB = 3x + 4 and AC which is twice of AB is equal to 11x - 17
2 (3x + 4) = 11x - 17
6x + 8 = 11x - 17
8 + 17 = 11x - 6x
25 = 5x
5 = x
AC = CD = 11x - 17 ➡ 11×5 - 17 = 38
CD = 38 and DE = 49 - 38 = 11
Answer:
38.7°
Step-by-step explanation:
You are basically looking at a triangle with a 90° angle (check picture).
Since we are looking for the ramp's angle and are given the length of the opposite and the hypothenuse, we have to solve the following equation:
which is equivalent to
From the equation, h(t)=-16t^2+150. You are given the height of the
building which is 15ft and you are asked to find the time it takes to fall in
seconds.
h(t)=-16t^2+150
15=-16t^2+150
15 – 150 = -16t^2
-135 = -16t^2
t = 2.9 seconds
<span>Let the total hour of exam is 3hrs ie 180 minutes.( since answer required in minutes).
Let as assume maths questions be in x minutes.
Let the assume rest of the question is in y minutes.
Given that out of 320 qns 40 is maths qns.
therefore, maths qn is =40 and rest of qns is 280.
Also given the time of maths qns is twice of rest. They related in the following equation. ie x:y=2:1 ; x/y =2/1
ie x=2y
therefore 2x+y= 180 min ; ie 2(2y)+y= 180 ; y=36
therefore resolving for x = 2*36 = 72
time spent for maths qn is 2*x = 2* 72 =144min.
rest of maths question is 36 min.</span>
