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Answer:
A) Central angle has same measure as intercepted arc.
- mCE = mCD + mDE = 20° + 90° = 110°
B) Opposite angles of cyclic quadrilateral are supplementary.
- mRL = 2*m∠PQR - mPL = 2*74° - 72° = 76°
- m∠QPL = (1/2)mQRL = (1/2)(90° + 76°) = 83°
- m∠QRL = 180° - m∠QPL = 180° - 83° = 97°
- mQP = 360° - (90° + 76° + 72°) = 122°
C)
- m∠MLN = m∠MRN as same arc MN is intercepted
- m∠LMN is right angle as opposite side is diameter.
- ∠MNL is complementary with ∠MLN which is same as ∠MRN
- m∠MNL = 90° - 47° = 43°
D) Tangent secant angle is half of the intercepted arc.
<em>It seems wrong. Should be mQP instead of mQR</em>
- mQP = 2*m∠RQP = 2*74° = 148°
Answer:A. 140
Step-by-step explanation:
1/2(5)(7)(8)
<span>Stress that all the relationships are multiply or divide (not add or subtract). Stress that the same operations are done on both sides. Stress that the directions of the arrows are important. Acknowledge that there are several different correct ways to solve ratio problems.</span>
Hello from MrBillDoesMath!
Answer: 70%
Discussion:
Goal = 5000
Amount raised = 3500
Percent of goal reached = ( 3500/5000) * 100 =
0.7 * 100 = 70
Thank you,
MrB
