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Bingel [31]
2 years ago
12

Please help, the homework is due in a few hours​

Mathematics
1 answer:
givi [52]2 years ago
4 0

Answer:

the aswer is 2

Step-by-step explanation:

this is because 10/5=2

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What is the circle's circumference? The diameter of a circle is 6 millimetres.
dolphi86 [110]

Answer:

C = 6pi or approximately 18.84 mm

Step-by-step explanation:

The circumference of a circle is

C = pi *d

C = pi *6

We can approximate pi by 3.14

C = 3.14*6

C =18.84

6 0
3 years ago
Evaluate Dx / ^ 9-8x - x2^
Solnce55 [7]
It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for \sqrt x.

In that case, you want to find the antiderivative,

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}

Complete the square in the denominator:

9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2

Now substitute x+4=5\sin y, so that \mathrm dx=5\cos y\,\mathrm dy. Then

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy

which simplifies to

\displaystyle\int\frac{5\cos 
y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy

Now, recall that \sqrt{x^2}=|x|. But we want the substitution we made to be reversible, so that

x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)

which implies that -\dfrac\pi2\le y\le\dfrac\pi2. (This is the range of the inverse sine function.)

Under these conditions, we have \cos y\ge0, which lets us reduce \sqrt{\cos^2y}=|\cos y|=\cos y. Finally,

\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C

and back-substituting to get this in terms of x yields

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C
4 0
3 years ago
Solve: p - 8 = -16<br><br><br><br> 20 characters rule
vlada-n [284]

Answer: p-8=-16

p=-16+8

p=-8

6 0
2 years ago
Read 2 more answers
Hello! Please help asap
ValentinkaMS [17]

Answer:

Hello! answer: 55

Step-by-step explanation:

55 + 35 = 90 HOPE THAT HELPS!

3 0
3 years ago
What are the zeros of the quadratic function? f(x)=2x2+x-3
alexgriva [62]

Answer: The zeros of the  quadratic function  are: 5/2+(1/2)*sqrt(31), 5/2-(1/2)*sqrt(31)

                 

Step-by-step explanation:

6 0
3 years ago
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