The least common factor of x and x squared is x
Answer: Only B
============================================
Explanation:
For situation A,
- x is the input and it represents the student's name.
- y is the output and it represents the colors the student likes.
The pairing (x,y) tells us what a certain student likes in terms of color.
For example, the point (Allen, Red) tells us that Allen likes the color red. We could also have (Allen, Green) telling us he also likes green. Because the input "Allen" maps to more than one output, this means situation A is not a function. A function is only possible if any given input maps to exactly to one output. The input must be in the domain. The domain in this case is the set of all students in the classroom.
In contrast, Situation B is a function because a student will only have one favorite math teacher. I'm interpreting this to mean "number one favorite" and not a situation where a student can select multiple favorites.
Answer:
No solution
Step-by-step explanation:
I got it right on delta math, just dont write anything and turn that in and it should be correct.
<span>I think the answer is C but I would like someone to double check it for me please.</span>
Answer:
See proof below
Step-by-step explanation:
Two triangles are said to be congruent if one of the 4 following rules is valid
- The three sides are equal
- The three angles are equal
- Two angles are the same and a corresponding side is the same
- Two sides are equal and the angle between the two sides is equal
Let's consider the two triangles ΔABC and ΔAED.
ΔABC sides are AB, BC and AC
ΔAED sides are AD, AE and ED
We have AE = AC and EB = CD
So AE + EB = AC + CD
But AE + EB = AB and AC+CD = AD
We have
AB of ΔABC = AD of ΔAED
AC of ΔABC = AE of ΔAED
Thus two sides the these two triangles. In order to prove that the triangles are congruent by rule 4, we have to prove that the angle between the sides is also equal. We see that the common angle is ∡BAC = ∡EAC
So triangles ΔABC and ΔAED are congruent
That means all 3 sides of these triangles are equal as well as all the angles
Since BC is the third side of ΔABC and ED the third side of ΔAED, it follows that
BC = ED Proved
