Answer:
x=-6
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(6-2)/(-6-(-6))
m=4/(-6+6)
m=4/0
undefined
x=-6
Nearest 10: 4750
<span>Nearest 100: 4800 </span>
<span>Nearest 1000: 5000 </span>
<span>Nearest 10000: 0</span>
A straight line passing through the point (-2,1) and having a gradient of -3 yields the equation y = -3x - 5.
We know that a straight line is an infinitely long line with no curves on it. A straight line's equation is
y = mx + c...(1), where m is the gradient of the straight line and c is a constant.
Given that the gradient of the given straight line = m = -3.
Putting this value in (1), we get
y = -3x + c ...(2)
Again, the given straight line passes through the point (-2,1). So, we can put x = -2 and y = 1 to get the value of the constant c.
So, 1 = (-3)(-2) + c
i.e. 6 + c = 1
i.e. c = 1 - 6 = -5
(2) can be written as
y = -3x - 5
Therefore the equation of the given straight line is
y = -3x - 5
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Answer:
95% provides more information
Step-by-step explanation:
The confidence interval is obtained by using the relation :
Xbar ± Zcritical * σ/√n
(Xbar - (Zcritical * σ/√n)) = 5.22 - - - (1)
(Xbar + (Zcritical * σ/√n)) = 5.98 - - (2)
Adding (1) and (2)
2xbar = 5.22 + 5.98
2xbar = 11.2
xbar = 11.2 / 2 = 5.6
Margin of Error :
Xbar - lower C.I = Zcritical * σ/√n
Zcritical at 90% = 1.645
5.6 - 5.22 = 1.645 * (σ/√n)
0.38 = 1.645 * (σ/√n)
(σ/√n) = 0.38 / 1.645 = 0.231
Therefore, using the se parameters to construct at 95%
Zcritical at 95% = 1.96
Margin of Error = Zcritical * σ/√n
Margin of Error = 1.96 * 0.231 = 0.45276
C.I = xbar ± margin of error
C. I = 5.6 ± 0.45276
C.I = (5.6 - 0.45276) ; (5.6 + 0.45276)
C. I = (5.147 ; 6.053)
Hence, 95% confidence interval provides more information as it is wider.