Do you still need the answer to this or nah?
Answer:
This is the rate at which the radius of the balloon is changing when the volume is 300

Step-by-step explanation:
Let
be the radius and
the volume.
We know that the gas is escaping from a spherical balloon at the rate of
because the volume is decreasing, and we want to find 
The two variables are related by the equation

taking the derivative of the equation, we get

With the help of the formula for the volume of a sphere and the information given, we find
![V=\frac{4}{3}\pi r^3\\\\300=\frac{4}{3}\pi r^3\\\\r^3=\frac{225}{\pi }\\\\r=\sqrt[3]{\frac{225}{\pi }}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r%5E3%5C%5C%5C%5C300%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r%5E3%5C%5C%5C%5Cr%5E3%3D%5Cfrac%7B225%7D%7B%5Cpi%20%7D%5C%5C%5C%5Cr%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B225%7D%7B%5Cpi%20%7D%7D)
Substitute the values we know and solve for 
![\frac{dV}{dt}=4\pi r^2 \frac{dr}{dt}\\\\\frac{dr}{dt}=\frac{\frac{dV}{dt}}{4\pi r^2} \\\\\frac{dr}{dt}=-\frac{12}{4\pi (\sqrt[3]{\frac{225}{\pi }})^2} \\\\\frac{dr}{dt}=-\frac{3}{\pi \left(\sqrt[3]{\frac{225}{\pi }}\right)^2}\\\\\frac{dr}{dt}=-\frac{3}{\pi \frac{225^{\frac{2}{3}}}{\pi ^{\frac{2}{3}}}}\\\\\frac{dr}{dt}=-\frac{3}{225^{\frac{2}{3}}\pi ^{\frac{1}{3}}} \approx -0.05537 \:\frac{ft}{h}](https://tex.z-dn.net/?f=%5Cfrac%7BdV%7D%7Bdt%7D%3D4%5Cpi%20r%5E2%20%5Cfrac%7Bdr%7D%7Bdt%7D%5C%5C%5C%5C%5Cfrac%7Bdr%7D%7Bdt%7D%3D%5Cfrac%7B%5Cfrac%7BdV%7D%7Bdt%7D%7D%7B4%5Cpi%20r%5E2%7D%20%5C%5C%5C%5C%5Cfrac%7Bdr%7D%7Bdt%7D%3D-%5Cfrac%7B12%7D%7B4%5Cpi%20%28%5Csqrt%5B3%5D%7B%5Cfrac%7B225%7D%7B%5Cpi%20%7D%7D%29%5E2%7D%20%5C%5C%5C%5C%5Cfrac%7Bdr%7D%7Bdt%7D%3D-%5Cfrac%7B3%7D%7B%5Cpi%20%5Cleft%28%5Csqrt%5B3%5D%7B%5Cfrac%7B225%7D%7B%5Cpi%20%7D%7D%5Cright%29%5E2%7D%5C%5C%5C%5C%5Cfrac%7Bdr%7D%7Bdt%7D%3D-%5Cfrac%7B3%7D%7B%5Cpi%20%5Cfrac%7B225%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%7D%7B%5Cpi%20%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%7D%7D%5C%5C%5C%5C%5Cfrac%7Bdr%7D%7Bdt%7D%3D-%5Cfrac%7B3%7D%7B225%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%5Cpi%20%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%7D%20%5Capprox%20-0.05537%20%5C%3A%5Cfrac%7Bft%7D%7Bh%7D)
Answer:
54.514 rev/min
Step-by-step explanation:
Data provided in the question:
Speed of the cable car = 12.65 miles per hour
Diameter of the rotating wheel, d = 6.5 feet
Now,
The speed of rotation of the wheel will be equal to the speed of the cable car
thus,
The speed of rotation of the wheel = 12.65 miles per hour
also,
1 miles = 5280 feets
1 hour = 60 minutes
Thus,
The speed of rotation of the wheel = 
= 1113.2 ft/ min
Circumference of the wheel = πd
= 6.5π feet
= 20.42 feet
Therefore,
The speed of rotation of the wheel in revolutions per minute
= 1113.2 ÷ 20.42 rev/min
= 54.514 rev/min
Answer:
x = 31
ROS = 62
Step-by-step explanation:
QOR + ROS = 90 degrees as indicated by the box
28+ 2x = 90
Subtract 28 from each side
2x = 90 -28
2x = 62
Divide by 2
2x/2 = 62/2
x = 31
ROS = 2x = 2*31 = 62
Answer:
It could be 2:5 or 6pi:15pi
Step-by-step explanation:
If you write the ratio of the surface area as a fraction, you would get
. Simplifying it would leave
. But this is NOT the answer because that is the ratio of the surface area. You have to square root it to find the scale factor. The square root is
. The answers would be 2:5 and 6pi:15pi.