Astronomers observe a distant star. They expect the planet to orbit the star approximately 3/4 times every 19 years. About how m
1 answer:
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Answer:
The daily value for saturated fat is 20g.
Step-by-step explanation:
Percentage problems can be solved by rule of three
In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.
When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too. In this case, the rule of three is a cross multiplication.
When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease. In this case, the rule of three is a line multiplication.
A percentage problem is an example where the relationship between the measures is direct.
The problem states that 1g is 5% of the daily value for saturated fat. The daily value(100%) for saturated fat is x, so:
1g - 5%
xg - 100%
5x = 100
x = 20g
The daily value for saturated fat is 20g.
Answer:
And then the percentage between 24 and 40 would be
Step-by-step explanation:
For this problem we have the following parameters given:
And for this case we want to find the percentage of lightbulb replacement requests numbering between 24 and 40.
From the empirical rule we know that we have 68% of the values within one deviation from the mean, 95% of the values within 2 deviations and 99.7% within 3 deviations.
We can find the number of deviations from themean for the limits with the z score formula we got:
And replacing we got:
And then the percentage between 24 and 40 would be
Answer:
60°
Step-by-step explanation:
Given :
DAB= (180 – 3x) °,
mZ B= (6x – 40) °, and
m ZC = (x+20) °.
DAB = mZ B + m ZC ( the exterior angle equal the sum of the two opposite interior angles)
180 - 3x = (6x - 40) + (x + 20)
180 - 3x = 6x - 40 + x + 20
180 - 3x = 6x + x - 40 + 20
180 - 3x = 7x - 20
180 + 20 = 7x + 3x
200 = 10x
x = 200/10
x = 20
Angle B = 6x - 40 = 6(20) - 40 = 120 - 40 = 80
Angle C = x + 20 = 20 + 20 = 40
BAC = 180 - (80 + 40) (SUM OF ANGLES IN A TRIANGLE)
BAC = 180 - 120
BAC = 60°
