Answer:
20 miles $80
Step-by-step explanation:
20 miles
P%5Bc%5D%2820%29=20%2B3%2820%29=20%2B60=80
$80
Answer:
The answer is "Option C"
Step-by-step explanation:
The using formula![= (1+\frac{r}{n})^n -1](https://tex.z-dn.net/?f=%3D%20%281%2B%5Cfrac%7Br%7D%7Bn%7D%29%5En%20-1)
→r = rate
→ n = compounded value
In choice a:
When compounded is monthly
![n = 12](https://tex.z-dn.net/?f=n%20%3D%2012)
![\to (1+ \frac{0.040784}{12})^{12} = 1.0403-1 = 0.0403](https://tex.z-dn.net/?f=%5Cto%20%281%2B%20%5Cfrac%7B0.040784%7D%7B12%7D%29%5E%7B12%7D%20%3D%201.0403-1%20%3D%200.0403)
In choice b:
When compounded is quarterly![4.0792\%](https://tex.z-dn.net/?f=4.0792%5C%25)
![n = 3\\\\\to (1+ \frac{0.040792}{12} )^{3} = 1.0102-1 = .0102](https://tex.z-dn.net/?f=n%20%3D%203%5C%5C%5C%5C%5Cto%20%281%2B%20%5Cfrac%7B0.040792%7D%7B12%7D%20%29%5E%7B3%7D%20%3D%201.0102-1%20%3D%20.0102)
In choice c:
Whenn compounded is daily ![4.0730 \%](https://tex.z-dn.net/?f=4.0730%20%5C%25)
![n = 365\\\\\to (1+ \frac{0.040730}{12})^{365} = 3.328-1 = 2.328](https://tex.z-dn.net/?f=n%20%3D%20365%5C%5C%5C%5C%5Cto%20%281%2B%20%5Cfrac%7B0.040730%7D%7B12%7D%29%5E%7B365%7D%20%20%3D%203.328-1%20%3D%202.328)
In choice d:
When compounded is semiannually![4.0798\%](https://tex.z-dn.net/?f=4.0798%5C%25)
![n = 2\\\\\to (1+ \frac{0.040798}{12})^{2} = 1.0066-1 = 0.0066](https://tex.z-dn.net/?f=n%20%3D%202%5C%5C%5C%5C%5Cto%20%281%2B%20%5Cfrac%7B0.040798%7D%7B12%7D%29%5E%7B2%7D%20%3D%201.0066-1%20%3D%200.0066)
Answer:
Step-by-step explanation:
(((22•5ax2) + 25ax) + 15a) - 5 = 0
Step 2 :
Step 3 :
Pulling out like terms :
3.1 Pull out like factors :
20ax2 + 25ax + 15a - 5 =
5 • (4ax2 + 5ax + 3a - 1)
Equation at the end of step 3 :
5 • (4ax2 + 5ax + 3a - 1) = 0
Step 4 :
Equations which are never true :
4.1 Solve : 5 = 0
Answer:
We know that:
Energy released by fusion of hydrogen in 1 liter of solution A = 7.6x10^10 J
Energy used daily in a certain family home = 3x10^4 J
(you did not write the units, so i suppose that are the same in both cases)
Then, if x is the number of liters of solution A used, the energy produced will be:
E(x) = x*7.6x10^10 J
And we want this equal to 3x10^4
then:
E(x) = x*7.6x10^10 J = 3x10^4 j
now we solve this for x.
x = (3x10^4 j)/(7.6x10^10 j) = 3.9x10^-7
Then you need to use 3.9x10^-7 L of solution a.