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3 years ago

What is the probability that a point chosen at random in the regular hexagon lies in the shaded region? A 1/3 B 2/5 C 1/2 D 2/3

Mathematics

2 answers:

kondaur [170]3 years ago

8 0

Answer: option A) 1/3

Justification:

1) The probability that a point chosen at random <span>in the regular hexagon lies in the shaded region is equal to:

area of the shaded region
---------------------------------------
   area of the hexagon

2) The hexagon is formed by 6 equal triangles and the shaded area is formed by 2 of those triangles.

3) Therefor,naming x the area of one triangle, the the above fraction is equal to:

area of two triangles           2x
------------------------------- =    --------   = 2/6 = 1/3
area of six triangles          6x

And that is the answer: 1/3
</span>

aleksandr82 [10.1K]3 years ago

7 0

C Is the final answer

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Answer:

Parallel: G and F

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3 years ago

What unit is used to measure the density of a solid?

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2 years ago

Four times a number is equal to the number increased by 15. Enter the equation that represents Karla's sentence into the box. Us

Montano1993 [528]

Answer:

The equation that represents Karla's sentence is 4y = y + 15

Step-by-step explanation:

From the question,

Four times a number is equal to the number increased by 15. To write the equation that represents the sentence, we will have to use a variable to represent the unknown number.

Since we are asked to use y for the variable, that is, let the number be y

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The statement, "four times a number" will be

4×y = 4y

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The number increased by 15 means y + 15.

Hence, the equation becomes

4y = y + 15

This is the equation that represent Karla's sentence.

If desired,

The unknown number can be determined by solving for y in the equation

4y = y + 15

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4y - y = 15

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Then, Divide both sides by 3

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2 years ago

Show that the roots of the equations

harkovskaia [24]

Answer:

The roots are real and distinct.

Step-by-step explanation:

Given the following equation:

$x^{2} + kx - k -2 =0$

In this problem, a = 1, b = k and c = -k - 2

The discriminant is b² - 4ac, and for the roots to be real and distinct, it must be at least or greater than 0.

We get,

(k)²- 4(1)(-k - 2) = 1 - 4(-k - 2)

= k² + 4k + 8

Let's check:

At k = -2,

$(-2)^{2} + 4(-2) + 8 = 4 - 8 + 8 = 4


$

At k = 0,

$(0)^2 + 4(0) + 8 = 8$

At k = -100,

$(-100)^2 + 4(-100) + 8 = 10,000 - 400 + 8 = 9608$

Therefore, we can conclude that for all values of k, the roots are real and distinct.

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2 years ago

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Answer:

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