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aleksandr82 [10.1K]
4 years ago
14

A plumber has a piece of pipe that is 2-meter long. He needs to cut it into sections that are 10 centimeters long. How many sect

ions will he be able to cut?
Mathematics
1 answer:
hjlf4 years ago
3 0
He would be able to cut 20 sections:)
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Can y’all help me with these plz
nalin [4]

Answer:

1)  160 (less than or equal to) 42+65+x      OR      53

2)  2000 (greater than or equal to) 637+x    OR    $1363

3)  1st piece: 5ft

    2nd piece: 10ft

    3rd piece: 6ft

Step-by-step explanation:

1) You must reach at least 160 blankets. Some have already been added, so just add the total to "x"

2) Your brother already spent $637 of 2000 dollars.

3 0
3 years ago
Simplify:(-<br> 17)^8÷(-17)^2
lidiya [134]

The simplified answer is -17^6\\

If you are dividing powers with like terms you subtract the denominator to the numerator.

\frac{-17^8}{-17^2} = -17^6

8 0
3 years ago
Please help this is the last question and determines wether I pass or not
givi [52]
Hopefully I’m not too late, but here’s how I solved it. Basically, replace F with 68. Subtract 32 from both sides so your equation becomes 9/5C=36. Divide both sides by 9/5 so C is left but itself (C=36/1.8). The answer should come out to 20. If you want to check my answer, plug 20 into the equation. Multiply 20x9/5 which equals 36. Add 36 and 32 together to get 68. Hope this helps
3 0
3 years ago
THE NUMBER THAT IS 7 MORE THAN THE NUMBER N
Musya8 [376]
N+7
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6 0
4 years ago
Read 2 more answers
Etermine two pairs of polar coordinates for the point (2, -2) with 0° ≤ θ &lt; 360°.
Jet001 [13]

To convert from rectangular to polar we will use these 2 formulas:

r^2=x^2+y^2 and

tan\theta=\frac{y}{x}.

The r value found serves as the first coordinate in our polar coordinate, and the angle serves as the second coordinate of the pair. We are told to find 2. Since the r value will always be the same (it's the length of the hypotenuse created in the right triangle we form when determining our angle theta), the angle is what is going to be different in our coordinate pairs. We use the x and y coordinates from the given rectangular coordinate to solve for the r in both our coordinate pairs.

r^2=2^2+ -2^2 which gives us an r value of 2\sqrt{2}. That's r for both coordinate pairs. Now we move to the angle. Setting up according to our formula we have

tan\theta =\frac{-2}{2} =-1.

This asks the question "what angle(s) has/have a tangent of -1?". That's what we have to find out! Since the tangent ratio is y/x AND since it is negative, it is going to lie in a quadrant where x is negative and y is positive, AND where x is positive and y is negative. Those quadrants are 2 and 4. In QII, x is negative so the tangent ratio is negative here; in QIV, y is negative so the tangent ratio is negative here as well. Now, if we type inverse tangent of -1 into our calculators in degree mode, we get that the angle that has a tangent of -1 is -45. Measured from the positive x axis, -45 does in fact go into the fourth quadrant. However, since the inverse tangent of -1 is -45, we also have a 45 degree angle in the second quadrant. Those are reference angles, mind you. A 45 degree angle in QII has a coterminal angle of 135 degree; a 45 degree angle in QIV has a coterminal angle of 315. If you don't understand that, go back to your lesson on reference angles and coterminal angles to see what those are. So our polar coordinates for that rectangular coordinate are

(2\sqrt{2},135) and

(2\sqrt{2},315)

8 0
3 years ago
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