4 ten thousands 4 thousands x 10 in standard form

PLSSS HELP IMMEDIATELY!!!!!!! only answer if u know. i’ll be giving brainiest if u don’t leave a link.

podryga [215]

Answer:

1. isosceles because two of the sides are equal

2. right because there is a right angle

Step-by-step explanation:

7 0

3 years ago

A group of 6p people are renting a vacation house together the price of the rental is 3p to the 2nd power if they split the cost

Tanya [424]

So we just do
cost/number of people=cost per 1 person
so
(6p)/(3p^2)
remember that you can split it up and make ones
$\frac{6p}{3p^{2}}$ = $\frac{6}{3p}$ times $\frac{p}{p}$ = $\frac{2}{1p}$ times $\frac{p}{p}$ times $\frac{3}{3}$ = $\frac{2}{1p}$ times 1 times 1=2/p

easy way is
remember that
(x^m)/(x^n)=x^(m-n)
so
(6p)(3p^2)=6/(3p=2/p=2p^-1

each member pays 2/p

4 0

4 years ago

How do you add parentheses to 9 + 12 / 3 + 4 / 2 + 1 * 2 to make the answer 12? Please help quick.

morpeh [17]

Answer:

so the final answer is =17

Step-by-step explanation:

9+12/3=13+4/2=2+1*2=2 the answer is 13+2+2=17

4 0

2 years ago

The sum of two numbers is 52. The greater number is 4 more than the smaller number. Which equation can be used to solve for the

Gnesinka [82]

One option for the final answer is 30 and 22...
I think I would use the second answer that you provided

5 0

3 years ago

Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your

Darina [25.2K]

Answer:

Given definite integral as a limit of Riemann sums is:

$\lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]$

Step-by-step explanation:

Given definite integral is:

$\int\limits^7_4 {\frac{x}{2}+x^{3}} \, dx \\f(x)=\frac{x}{2}+x^{3}---(1)\\\Delta x=\frac{b-a}{n}\\\\\Delta x=\frac{7-4}{n}=\frac{3}{n}\\\\x_{i}=a+\Delta xi\\a= Lower Limit=4\\\implies x_{i}=4+\frac{3}{n}i---(2)\\\\then\\f(x_{i})=\frac{x_{i}}{2}+x_{i}^{3}$

Substituting (2) in above

$f(x_{i})=\frac{1}{2}(4+\frac{3}{n}i)+(4+\frac{3}{n}i)^{3}\\\\f(x_{i})=(2+\frac{3}{2n}i)+(64+\frac{27}{n^{3}}i^{3}+3(16)\frac{3}{n}i+3(4)\frac{9}{n^{2}}i^{2})\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{3}{2n}i+\frac{144}{n}i+66\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{291}{2n}i+66\\\\f(x_{i})=3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]$

Riemann sum is:

$= \lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]$

4 0

4 years ago