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Sladkaya [172]
3 years ago
10

Lewis rolls a number cube and then chooses a card from a set of cards numbered 1 through 5. What is the probability that he will

roll an even number and choose an even numbered card?
Mathematics
1 answer:
IceJOKER [234]3 years ago
3 0

Answer:

\frac{1}{5}=0.2

Step-by-step explanation:

The general formula for a probability is:

P=\frac{FavorableEvent}{TotalEvents}

The favorable events for the cube to fall in a even number are:

2, 4, and 6 ⇒ <u>3 favorable events</u>

and in the cube the total events are:

1, 2, 3, 4, 5, 6 ⇒ <u>6 total events</u>

So the probability of rolling an even number in the cube is:

P=\frac{3}{6}\\\\\\ P=\frac{1}{2}

Now we do something similar to find the probability to choose a card with an even number.

The favorable events for an even numbered card are:

2, 4 ⇒<u> 2 favorable events</u>

and the total number of events in the cards is:

1, 2, 3, 4, 5 ⇒ <u>5 total events</u>

Thus, the probability to choose an even numbered card (according to the probability formula) is:

P=\frac{2}{5}

And finally, since we want both things to happen we must multiply both obtained probabilities:

  • the probability that he will roll an even number and choose an even numbered card:

P=\frac{1}{2}*\frac{2}{5} \\ \\P=\frac{2}{10} \\\\P=\frac{1}{5} =0.2

The probability is 1/5 which is equal to 0.2 or 20%

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A zoologist is studying four very closely related feline species. She wishes to compare their gestation periods. An observationa
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Answer:

p_v= 0.01

Since the significance level is 0.05 we see that pv so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different, NOT to conclude that the all the means are different.

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".  

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"  

Solution to the problem

The hypothesis for this case are:

Null hypothesis: \mu_{A}=\mu_{B}=\mu_{C}= \mu_D

Alternative hypothesis: Not all the means are equal \mu_{i}\neq \mu_{j}, i,j=A,B,C,D

In order to find the mean square between treatments (MSTR), we need to find first the sum of squares and the degrees of freedom.

If we assume that we have p=4 groups and on each group from j=1,\dots,p we have n_j individuals on each group we can define the following formulas of variation:  

SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2  

SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2  

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2  

And we have this property  

SST=SS_{between}+SS_{within}  

And in order to test this hypothesis we need to ue an F statistic and for this case the p value calculated is

p_v= 0.01

Since the significance level is 0.05 we see that pv so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

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3 years ago
QUESTION 94
sattari [20]

Answer: 34.3%

Step-by-step explanation:

Given:\ 12/35\ flights\ on\ time

To find the percent, divide then multiply by 100:

\frac{12}{35} = 0.343\times100=\large\boxed{34.3}

4 0
1 year ago
Which list is in order from least to greatest? A) 9.4 * 10^-8, 9.25 * 10^-6, 2.5 * 10^3, 7* 10^3 B) 2.5 *10^3, 7 * 10^3, 9.25 *
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ANSWER

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EXPLANATION

The numbers are given in standard form.

The first criteria we will use to order them is the exponents.

The bigger the exponents the bigger the number.

The second criteria is that, if the exponents of any two numbers are the same, then we use the numbers multiplying the powers of 10 to order.

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The correct choice is A.

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Answer:

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Step-by-step explanation:

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