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Nataly_w [17]
3 years ago
14

Q # 19 The data below shows the. number of hours a week on average group of students spend volunteering for community service pr

oject.What is a cumulative frequency table that represents the data.
4 5 10 21 6 2 9 8 12 15 8 14 6 4 6 11 3 2 9 16 22 23

Mathematics
1 answer:
alisha [4.7K]3 years ago
7 0
If those two are your only choices then the answer is none of the above. 

<em>Attached is a cumulative frequency table for your data.</em>

If you take a look at the two tables given, the frequencies were not tallied properly. If the frequency column is wrong, then the cumulative frequency will be wrong. 

The answer is then none of the above or find one that matches the table attached. 

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If fence poists are to be placed in a row 7 feet apart, how many posts are needed for 210 feet of fence?
ollegr [7]

Answer:

31

Step-by-step explanation:

210 ft ÷ 7 ft = 30

There are 30 7-ft lengths of fence.

Think of putting a post at the end of each 7-ft length. That means you need 30 posts. Now you must add 1 post for the beginning.

Answer: 31

8 0
2 years ago
What expression is this?
Vinvika [58]

Answer:

the 3rd choice po

ang sagot po

6 0
2 years ago
Write out the first four terms of the series to show how the series starts. Then find the sum of the series or show that it dive
Nostrana [21]

Answer:

The first four terms of the series are

(9+3),(\frac97+\frac35),(\frac9{7^2}+\frac3{5^2}),(\frac9{7^3}+\frac3{5^3})

\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n} = 14.25

Step-by-step explanation:

We know that

Sum of convergent series is also a convergent series.

We know that,

\sum_{k=0}^\infty a(r)^k

If the common ratio of a sequence |r| <1 then it is a convergent series.

The sum of the series is \sum_{k=0}^\infty a(r)^k=\frac{a}{1-r}

Given series,

\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}

=(9+3)+(\frac97+\frac35)+(\frac9{7^2}+\frac3{5^2})+(\frac9{7^3}+\frac3{5^3})+.......

The first four terms of the series are

(9+3),(\frac97+\frac35),(\frac9{7^2}+\frac3{5^2}),(\frac9{7^3}+\frac3{5^3})

Let

S_n=\sum_{n=0}^\infty \frac{9}{7^n}    and     t_n=\sum_{n=0}^\infty \frac{3}{5^n}

Now for S_n,

S_n=9+\frac97+\frac{9}{7^2}+\frac9{7^3}+.......

    =\sum_{n=0}^\infty9(\frac 17)^n

It is a geometric series.

The common ratio of S_n is \frac17

The sum of the series

S_n=\sum_{n=0}^\infty \frac{9}{7^n}

    =\frac{9}{1-\frac17}

    =\frac{9}{\frac67}

    =\frac{9\times 7}{6}

    =10.5

Now for t_n

t_n= 3+\frac35+\frac{3}{5^2}+\frac3{5^3}+.......

    =\sum_{n=0}^\infty3(\frac 15)^n

It is a geometric series.

The common ratio of t_n is \frac15

The sum of the series

t_n=\sum_{n=0}^\infty \frac{3}{5^n}

    =\frac{3}{1-\frac15}

    =\frac{3}{\frac45}

    =\frac{3\times 5}{4}

    =3.75

The sum of the series is \sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}

                                        = S_n+t_n

                                       =10.5+3.75

                                       =14.25

4 0
3 years ago
Mr Davis buys 30 tickets for the drama club to attend a play. The tickets cost n dollars each for a total of $360
nalin [4]

Answer:

the answer is F. because n x 30 would = 360 and the n would be 12 so he paid 12 dollars per ticket and I got that answer by dividing the two numbers 30 and 360

brainliest plz

5 0
3 years ago
Which is the following points is NOT a solution to the inequality y &gt; - x + 3? —a. ( -2,6)b. (5,-1)c. (2,0)d. (0,3)
CaHeK987 [17]

Given -

y > - x + 3

To Find -

The points which is NOT a solution to the inequality

Step-by-Step Explanation -

We will put the value of each in inequality and then see if it satisfies the given condition or not.

a. ( -2,6)

So, x = -2 and y = 6 in y > - x + 3

= 6 > - (-2) + 3

= 6 > 5 (Correct Solution)

b. (5,-1)

So, x = 5 and y = -1 in y > - x + 3

= -1 > -5 + 3

= -1 > -2 (Correct Solution)

c. (2,0)

So, x = 2 and y = 0 in y > - x + 3

= 0 > -2 + 3

= 0 > 1 (Incorrect Solution)

d. (0,3)

So, x = 0 and y = 3 in y > - x + 3

= 3 > -0 + 3

= 3 > 3 (Incorrect Solution)

Final Answer -

The points which is NOT a solution to the inequality =

c. (2,0)

d. (0,3)

3 0
11 months ago
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