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Nataly_w [17]
3 years ago
14

Q # 19 The data below shows the. number of hours a week on average group of students spend volunteering for community service pr

oject.What is a cumulative frequency table that represents the data.
4 5 10 21 6 2 9 8 12 15 8 14 6 4 6 11 3 2 9 16 22 23

Mathematics
1 answer:
alisha [4.7K]3 years ago
7 0
If those two are your only choices then the answer is none of the above. 

<em>Attached is a cumulative frequency table for your data.</em>

If you take a look at the two tables given, the frequencies were not tallied properly. If the frequency column is wrong, then the cumulative frequency will be wrong. 

The answer is then none of the above or find one that matches the table attached. 

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PLEASE HELP!
eduard

Answer:

B) 2828.427g

Step-by-step explanation:

Hope this helps!

7 0
2 years ago
Read 2 more answers
Jessica picked oranges for 2 days during school vacation. She was paid $0.45 per basket for the first 100 baskets picked each da
Mama L [17]

Answer:

$91.75

Step-by-step explanation:

Jessica is paid:

  • $0.45 per basket for the first 100 baskets picked;
  • $0.50 per basket for all baskets over 100 picked.

1st day:

Jessica picked 65 baskets of oranges (less than 100)

Jessica is paid 65\cdot \$0.45=\$29.25

2nd day:

Jessica picked 135 baskets of oranges (35 more than 100)

Jessica is paid 100\cdot \$0.45+35\cdot \$0.50=\$45+\$17.50=\$62.50

Altogether Jessica is paid

\$29.25+\$62.50=\$91.75

4 0
3 years ago
If m1 = 70 what is m8?
Inessa [10]
Sh*t i had the answer but i lost my train of thought sorry :(

6 0
3 years ago
Read 2 more answers
List Least to Greatest, 2/5, 1/3, 4/9, or 3/4 Please help
Ilya [14]
2/5 1/3 4/9 3/4. that's the answer
6 0
3 years ago
The atmospheric pressure on an object decreases as altitude increases. If a is the height (in km) above sea level, then the pres
seraphim [82]

Answer:

373.8mmHg

Step-by-step explanation:

a =height (in km) above sea level,

the pressure P(a) (in mmHg) is approximated given as

P(a) = 760e–0.13a .

To determine the atmospheric pressure at 5.458 km, then we will input into the equation

P(5.458km) = 760e–0.13a .

= 760e^(-0.13×5.458)

=760e^-(0.70954)

= 760×0.4919

=373.8mmHg

Therefore, the atmospheric pressure at 5.458 km is 373.8mmHg

3 0
3 years ago
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