Going down the chart:
6
4
3
4
6
the brackets on the outside of the lxl makes the value positive or keeps the value positive. therefor if u have y=l-3l+3 y will still =6! hope this helps!
Answer:
m ≠1 ( all m in R except 1 )
Step-by-step explanation:
hello :
mx − y + 3 = 0.....(*)
(2m − 1)x − y + 4 = 0 ....(**)
multiply (*) by : -1 you have : -mx+y-3=0 ....(***)
(2m − 1)x − y + 4 = 0 ....(**)
add(***) and(**) : -mx+ (2m − 1)x+1 =0
(2m-m-1)x+1=0
(m-1)x = -1
this system have no solution if : m-1≠0 means : m ≠1
Answer:
Step-by-step explanation:
I have to go with 9r-18= -27 is my answer for your math
I’m not 100% certain but i’m pretty sure 1:3 works