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TiliK225 [7]
3 years ago
13

Through (2,2) slope 3/2

Mathematics
1 answer:
Mrac [35]3 years ago
4 0

Answer:

no info given :/

Step-by-step explanation:

...... ....

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Nancy and bill collect coins. Nancy has x coins. Bill has 7 coins fewer than 2 times the number of coins Nancy has. Write and si
pashok25 [27]

Answer:

total: 3x + 7

Step-by-step explanation:

Nancy = x

Bill = 2x + 7

together = 3x + 7

8 0
3 years ago
Answer the question below. Be sure to show your work
likoan [24]

ANSWER:

We have to find new side-lengths of PQR triangle.

Original sides are.

\begin{gathered} PQ\text{ = 8cm} \\ QR=17\operatorname{cm} \\ RP=15\operatorname{cm} \end{gathered}

After multiplying by 2.5 we get

\begin{gathered} PQ^{\prime}=2.5\times PQ=(8\times2.5)cm=20\operatorname{cm} \\ QR^{\prime}=(17\times2.5)cm=42.5\operatorname{cm} \\ RP^{\prime}=(15\times2.5)cm=37.5\operatorname{cm} \end{gathered}

These are the new sides of the P'Q'R' triangle.

5 0
1 year ago
What 9+1 please answer ​
Lunna [17]

Answer:

10

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
In the monthly payment formula , what value would you put for r if the interest rate is 5.7%?
natulia [17]
In the monthly payment formula r is the percentage rate as a decimal.

To turn a percentage into a decimal, move the decimal point 2 places to the left.
 5.7% becomes 0.057

3 0
3 years ago
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BRAINLIESTT ASAP! PLEASE HELP ME :)
antiseptic1488 [7]

Step-by-step explanation:

\displaystyle y = Acos(Bx - C) + D

According to this trigonometric function, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:

\displaystyle Phase\:[Horisontal]\:Shift → \frac{-\frac{2}{3}π}{2} = -\frac{π}{3} \\ Period → \frac{2}{2}π = π

Therefore we have our answer.

Extended Information on the trigonometric function

\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|

NOTE: Sometimes, your vertical shift might tell you to shift your graph below or above the <em>midline</em><em> </em>where the amplitude is.

I am joyous to assist you anytime.

3 0
3 years ago
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