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2 years ago

Find the slope of 6x – 3y = 5

Mathematics

1 answer:

sladkih [1.3K]2 years ago

3 0

Answer:

slope is 2

Step-by-step explanation:

simplify this equation so that you can get to "y ="

your equation is: 6x - 3y = 5

start by subtracting 6x from both sides: -3y = -6x - 5

then divide both sides by -3 to isolate y: y = 2x - 5/3

so now we can clearly see that the slope is 2, since that is what is right next to x

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Agata [3.3K]

Answer:

Step-by-step explanation:

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3 0

3 years ago

Assume that 3 digits are selected at random from the set {1,3,5,6,7,8} { 1 , 3 , 5 , 6 , 7 , 8 } and are arranged in random orde

Mumz [18]

Sample space is 36.so the probability must be 20/36.from three digits the maximum no.of number can be made is 6.

4 0

3 years ago

find the smaller of 2 consecutive integers, x, if the sum of the smaller is 3 times the larger is -5. Write an equation and solv

Leno4ka [110]

You have defined x to be the smaller of two consecutive integers. Then the larger will be (x+1). The given relation is

... (x) + 3(x+1) = -5 . . . . the smaller plus 3 times the larger is -5

... 4x + 3 = -5 . . . . . . . .simplify

... 4x = -8 . . . . . . . . . . subtract 3

... x = -2 . . . . . . . . . . . divide by the coefficient of x

The smaller of the two integers is -2.

5 0

3 years ago

A teacher categorized students by whether they regularly completed their homework (or not) and whether they passed the course (o

ella [17]

Probabilities are used to determine the chances of an event.

Let P represents the event that a student passes the course, and C represents the event that a student completes the assignment

(a) The probability a student passed the course given that they completed their homework?

From the table, we have:

$\mathbf{n(P\ n\ C) = 25}$

$\mathbf{n(C) = 30}$

So, the required probability is:

$\mathbf{Pr = \frac{n(P\ n\ C)}{n(C)}}$

This gives

$\mathbf{Pr = \frac{25}{30}}$

$\mathbf{Pr = 0.8333}$

Express as percentage

$\mathbf{Pr = 83.33\%}$

Hence, the probability a student passed the course given that they completed their homework is 83.33%

(b) The probability a student passed the course given that they didn't complete their homework

From the table, we have:

$\mathbf{n(P\ n\ C'= 7}$

$\mathbf{n(C') = 25}$

So, the required probability is:

$\mathbf{Pr = \frac{n(P\ n\ C')}{n(C')}}$

This gives

$\mathbf{Pr = \frac{7}{25}}$

$\mathbf{Pr = 0.28}$

Express as percentage

$\mathbf{Pr = 28\%}$

Hence, the probability a student passed the course given that they didn't complete their homework is 28%

(c) The probability a student completed their homework given that passed the course?

From the table, we have:

$\mathbf{n(P\ n\ C) = 25}$

$\mathbf{n(P) = 32}$

So, the required probability is:

$\mathbf{Pr = \frac{n(P\ n\ C)}{n(P)}}$

This gives

$\mathbf{Pr = \frac{25}{32}}$

$\mathbf{Pr = 0.78125}$

Express as percentage

$\mathbf{Pr = 78.125\%}$

Approximate

$\mathbf{Pr = 78.13\%}$

Hence, the probability a student completed their homework given that they passed the course is 78.13%

(d) The probability a student didn't complete their homework given that they didn't pass the course

From the table, we have:

$\mathbf{n(P'\ n\ C'= 18}$

$\mathbf{n(P) = 23}$

So, the required probability is:

$\mathbf{Pr = \frac{n(P'\ n\ C')}{n(P')}}$

This gives

$\mathbf{Pr = \frac{18}{23}}$

$\mathbf{Pr = 0.7826}$

Express as percentage

$\mathbf{Pr = 78.26\%}$

Hence, the probability a student didn't complete their homework given that they didn't pass the course is 78.26%