Find an equation of the plane that passes through the points p, q, and r. p(7, 2, 1), q(6, 3, 0), r(0, 0, 0)
Alona [7]
Answer:
x - 2y - 3z = 0
Step-by-step explanation:
The cross product of vectors rp and rq will give a vector that is normal to the plane:
... rp × rq = (-3, 6, 9)
Dividing this by -3 (to reduce it and make the x-coefficient positive) gives a normal vector to the plane of (1, -2, -3). Usint point r as a point on the plane, we find the constant in the formula to be zero. Hence, your equation can be written ...
... x -2y -3z = 0
Answer:
Step-by-step explanation:
I would not agree with Mai because 1km equals one thousand meters and soccer fields in general are 90 to 120 meters long and 45 to 90 meters wide so it impossible that she could have walked 1km even if she walked around it twice
Answer:
59 degrees
Step-by-step explanation:
1.8(15)+32=59
