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krek1111 [17]
3 years ago
13

Select the correct answer. Joe wants to enlarge the rectangular pumpkin patch located on his farm. The pumpkin patch is currentl

y 40 meters wide and 60 meters long. The new pumpkin patch will be 3x meters wider and 5x meters longer than that of the original pumpkin patch. Which of the following functions will give the area of the new pumpkin patch in square meters? A. f(x) = 15x2 + 420x + 2,400 B. f(x) = 15x2 C. f(x) = 15x2 + 2,400 D. f(x) = 15x2 + 380x + 2,400
Mathematics
1 answer:
Butoxors [25]3 years ago
3 0

Answer:

Option D

f(x)=15x^{2}+380x+2400

Step-by-step explanation:

Original dimensions are as follows

Length=60 m

Width=40 m

Area=60*40=2400 m^{2}

New dimensions

Length=(60+5x) m

Width=(40+3x) m

Area=(60+5x)\times (40+3x)

Area=60(40+3x)+5x(40+3x)=2400+180x+200x+15x^{2} and collecting like terms we obtain

Area=15x^{2}+380x+2400

Therefore,

f(x)=15x^{2}+380x+2400

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8.5 cm cable weighs = 52 grams

1 cm of cable weighs = \frac{52}{8.5}grams
                                      
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