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I am Lyosha [343]
3 years ago
11

Find the derivative of F(x)=-x^4+4x^3+ 70 for 0<=x<=3

Mathematics
1 answer:
timofeeve [1]3 years ago
8 0

Answer:

  -4x^3 +12x^2 for 0 < x < 3

Step-by-step explanation:

The power rule is appropriate:

  (d/dx)x^n = n·x^(n-1)

This is applied to each of the terms.

  F'(x) = -(4·x^3) +4(3x^2) +0

  F'(x) = -4x^3 +12x^2 . . . . for 0 < x < 3

__

The derivative is not defined at the endpoints of the interval, so F'(x) is only defined on (0, 3), not [0, 3].

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Question 3

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Since the scale is 1 : 75000 that is 1 cm : 75000 km, we want to find the actual distance of 16 cm on the map. Let x be the actual distance in km.

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Since the scale is 1 : 75000 , the scale for the area would be the square of this. So, 1² : 75000² = 1 : 5 625 000 000 which is 1 cm² : 5 625 000 000 km²

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So,  1 cm² : 5 625 000 000 km² = 12 cm² : z km²

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