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I am Lyosha [343]
3 years ago
11

Find the derivative of F(x)=-x^4+4x^3+ 70 for 0<=x<=3

Mathematics
1 answer:
timofeeve [1]3 years ago
8 0

Answer:

  -4x^3 +12x^2 for 0 < x < 3

Step-by-step explanation:

The power rule is appropriate:

  (d/dx)x^n = n·x^(n-1)

This is applied to each of the terms.

  F'(x) = -(4·x^3) +4(3x^2) +0

  F'(x) = -4x^3 +12x^2 . . . . for 0 < x < 3

__

The derivative is not defined at the endpoints of the interval, so F'(x) is only defined on (0, 3), not [0, 3].

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Answer:

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Step-by-step explanation:

THIS COMPLETE THE QUESTION

flagpole is supported by a wire fastened 60 feet from its base. The wire is 14 feet longer than the height it reaches on the flagpole. Find the length of the wire.

Let X be the length of the wire

Let y be the height of the pole

X= Y + 14

Y= X -14

We can form a right angle triangle form this, where X denote the Hypotenose, Y is the Opposite, and 60feet is the Adjacent.(CHECK THE ATTACHMENT FOR THE TRIANGLE)

Using Pythagoras theorem

X²= 60² + Y²

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if we subsitute for Y we have

X² = 3600 + (X -14)²

X² = 3600 +X² -14X-14X+196

X²-X²+ 28X= 3600+196

28X= 3796

X= 3796/28

=135.5ft

hence length of the wire is 135.5ft

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