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schepotkina [342]
3 years ago
6

Given that cos 26 degrees= 0.899, write the sine of a complementary angle

Mathematics
1 answer:
Vladimir [108]3 years ago
5 0

Complementary = angle+other angle = 90 degrees

90-26(given)=64
There is only one complimentary angle to any other angle, so 64 is the only other one. Sin(64)=.899

Sin(64)=cos(26)
This is because cosine and sine are actually THE SAME. Cosine exists because there's sine. Cosine is sine moved over on a graph a bit. The sine of any angle, plus 90degrees (or pi/2) is equal to the cosine of that angle

Cos(x)=sin(x+90) <--degrees
Cos(x)=sin(x+pi/2) <-- radians(from unit circle)

Unit circle has 90 degrees at pi/2 which is why that works. Using a graphing calculator in degrees, you'd use the first equation I gave to prove that they're equal, and in radian mode, you'd use the second one. Cosine is Co in front of sine. Co meaning complimentary, which is why the problem equals each other when solved
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Some parts are missing in the queston. Find attached the picture with the complete question

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                   \large\boxed{\large\boxed{161}}

Explanation:

Let's put the information in a table step-by step.

                                                (number of remaining students)

                                                        Juniors          Seniors

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  • Initially                                           J                     S
  • 15 seniors left                                                   S - 15
  • Twice juniors as seniors         2(S - 15)
  • 3/4 of the juniors left              1/4×2(S - 15)
  • 1/3 of seniors left                                             2/3×(S - 15)

At the end, there were 8 more seniors than juniors:

  • 2/3×(S - 15) -  1/4×2(S - 15) = 8

Now you have obtained one equation, which you can solve to find S, the number of senior students, and then the number of junior students.

Solve the equation:

2/3\times (S - 15) -  1/4\times 2(S - 15) = 8

  • Mutilply all by 12:

8(S - 15)-6(S - 15)=96

  • Distribution property:

8S-120-6S-90=96

  • Addtion property of equalities:

8S-6S=96+120+90

  • Add like terms:

2S=306

  • Division property of equalities:

S=306/2=153

That is the number of senior students that came out to the information meeting, but the number of students remaining to perform in the school musical is (from the table above):

2/3\times (S-15)+1/4\times 2(S-15)

Just substitute S with 153 fo find the number of students that remained to perfom in the musical:

          2/3\times (153-15)+1/4\times 2(153-15)\\ \\ 2/3(138)+1/2(138)

          161

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