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storchak [24]
3 years ago
12

How do you solve 2.5x-8=5x+12

Mathematics
1 answer:
LenaWriter [7]3 years ago
5 0
2.5x-8=5x+12
-2.5x -2.5x
--------------------
-8=2.5x+12
-12 -12
--------------------
-20 = 2.5x
------ ------
2.5 2.5
x=-8
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What is 5/3 to the power of 2
OleMash [197]
(5/3)= 1.667
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A line intersects the points(-22,-14) and (-18,-12). What is the slope-intercept equation for this line?
zaharov [31]

Hello there,

Well we are going to start off with the equation to find the slope based on the given points:

                                                    \frac{y_{2} - y_{1}  }{x_{2} -x_{1} }

Now using the two given points we are going to plug in and solve:

                                         \frac{(-12)-(-14)}{(-18)-(-22)} = \frac{2}{4} = \frac{1}{2}

From this you know that \frac{1}{2} is the slope of the equation. However, to find the y-intercept we are going to use y = mx+ b and plug in one of the points to solve:

                                        (-14) = \frac{1}{2} (-22) + b

                                        (-14) = (-11) + b

                                         -3 = b

That means that the y-intercept is at (0, -3). Lastly, we are just going to plug all this into the slope-intercept form:

                                       y = \frac{1}{2} - 3

Hope I helped,

Amna

6 0
3 years ago
How to find an acute angle between two lines?
Goryan [66]
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Multiplication in GF(24 ): Compute A(x)B(x) mod P(x) in GF(24 ) using the irreducible polynomial P(x) = x 4 + x + 1, where A(x)
tankabanditka [31]

Answer:

Step-by-step explanation:

hello,

i advice you check the question again if it is GF(2^{4}) or GF(24). i believe the question should rather be in this form;

multiplication in GF(2^{4}): Compute A(x)B(x) mod P(x) = x^{4} + x+1, where A(x)=x^{2}+1, and B(x)=x^{3} + x+1.

i will solve the above question and i believe with this you will be able to solve any related problem.

A(x)B(x)=(x^{2} +1) (x^{3}+x+1) mod (x^{4}+x+1  ) = (x^{5} +x^{3}+x^{2}  ) + (x^{3}+x+1  ) mod (x^{4} + x+1 )

= x^{5}+2x^{3} +x^{2}  + x + 1 mod(x^{4}+x+1  )

=2x^{2} +1

please note that the division by the modulus above we used

\frac{x^{5}+2x^{3}+x^{2} +1  }{x^{4}+x+1}= x+\frac{2x^{3} +1}{x^{4}+x+1}

5 0
3 years ago
Plese tell how to solve this​
klasskru [66]

Answer:

hope you understand the answers

8 0
3 years ago
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