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3 years ago

12

Which number is a common factor of 50 and 125? A) 15 B) 25 C) 45 D) 50 F) Jk, I'm just joking with you guys, anyone who answers

first can be brainliest

1 answer:

oksian1 [2.3K]3 years ago

6 0

Answer:

The answer is *drum roll* ... 25!

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If Jenna has $50.00 and Leon has $65.00 and they both want to by a baby bunny giant doll that cost $115.43 how much do they spli

patriot [66]

Even if they both spent all of their money, they would still be $0.43 short.

Leon’s $65 and Jennas $50 makes $115. Since they need $115.43, it doesn’t matter how they split the money as they wouldn’t have enough

Hope this helps :)

3 0

2 years ago

Read 2 more answers

A pole is used to support an observation platform. The top of the pole is secured by two guy wires, one 18 and the other 21 feet

Harman [31]

Let $A$ be the point on the ground to with the 18 foot guy is anchored and $D$ the point on the ground to with the 21 foot guy is anchored.

We can conclude that the <span>the two wires at the points where they are anchored are 21 feet apart. Check the procedures in the picture attached.</span>

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2 years ago

For which function is f(x) equal to f^1(x) ( answer choices in picture )

Sonja [21]

Answer:

C. $f(x)=\frac{x+1}{x-1}$

Step-by-step explanation:

Let's find the inverse of each of the given options.

Option A:

$f(x)=\frac{x+6}{x-6}\\y=\frac{x+6}{x-6}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+6}{y-6}$

Rewrite in terms of 'y'. This gives,

$x(y-6)=y+6\\xy-6x=y+6\\xy-y=6x+6\\y=\frac{6x+6}{x-1}$

The given function $y=\frac{6x+6}{x-1}\ne y=\frac{x+6}{x-6}$

So, option A is incorrect.

Option B:

$f(x)=\frac{x+2}{x-2}\\y=\frac{x+2}{x-2}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+2}{y-2}$

Rewrite in terms of 'y'. This gives,

$x(y-2)=y+2\\xy-2x=y+2\\xy-y=2x+2\\y=\frac{2x+2}{x-1}$

The given function $y=\frac{2x+2}{x-1}\ne y=\frac{x+2}{x-2}$

So, option B is incorrect.

Option C:

$f(x)=\frac{x+1}{x-1}\\y=\frac{x+1}{x-1}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+1}{y-1}$

Rewrite in terms of 'y'. This gives,

$x(y-1)=y+1\\xy-x=y+1\\xy-y=x+1\\y=\frac{x+1}{x-1}$

The given function $y=\frac{x+1}{x-1}\ equals\ y=\frac{x+1}{x-1}$

So, option C is correct.

Option D:

$f(x)=\frac{x+5}{x-5}\\y=\frac{x+5}{x-5}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+5}{y-5}$

Rewrite in terms of 'y'. This gives,

$x(y-5)=y+5\\xy-5x=y+5\\xy-y=5x+5\\y=\frac{5x+5}{x-1}$

The given function $y=\frac{5x+5}{x-1}\ne y=\frac{x+6}{x-6}$

So, option D is incorrect.

Therefore, only option C is correct.

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3 years ago

You invest $700 in an account that pays an interest rate of 6.5%, compounded continuously.

Nina [5.8K]

Please include the instructions when you post a question. Thanks.

Use the formula A = P*e^(rt).

Here, A = $700*e^(0.065*t), where t is the # of years (which you have not yet included in your post).

As an example: After 2 years you'll have A = $700*e^(0.065*2), or A=$797.18, in your account.

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2 years ago

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Line FG contains points F(3,7) and G (-4,-5)

sdas [7]

What are you supposed to be finding? Give More Information Plz. <span />

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3 years ago