Answer:
D
Step-by-step explanation:
Given a tangent and a secant from an external point to the circle, then
The product of the external part and the whole secant is equal to the square of the tangent, that is
8(8 - 6 + 2x) = 12²
8(2 + 2x) = 144 ( divide both sides by 8 )
2 + 2x = 18 ( subtract 2 from both sides )
2x = 16 ( divide both sides by 2 )
x = 8
Then
GH = - 6 + 2x = - 6 + 2(8) = - 6 + 16 = 10 → D
There is no definite way to answer this question without further, more detailed information. I am truly sorry I am unable to answer this with the information provided.
Answer:
(1, -6)
Step-by-step explanation:
the layout of your question is kind of confusing, but i'm guessing this is the system of equations
x = -y - 5
-3x + 7y = -45
plug in x to the second equation
-3(-y - 5) + 7y = -45
distribute
3y + 15 + 7y = -45
combine like terms
10y = - 60
divide by 10
y = -6
plug y into first equation
x = -(-6) - 5
x = 6 - 5
x = 1
Answer:
B
Step-by-step explanation: