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IRISSAK [1]
3 years ago
8

Find the value of x to the nearest tenth.I will mark the brainlest

Mathematics
1 answer:
Feliz [49]3 years ago
8 0

Answer:

The value of x nearest to tenth is, 1.5 units

Step-by-step explanation:

In right angle triangle as shown in figure

by definition of tangent ratio i,e   \tan \theta = \frac{opposite side}{Adjacent side}

\tan 37^{\circ} = \frac{x}{2.1}

0.7535540501= \frac{x}{2.1}

or

x = 0.7535540501 \times 2.1 = 1.58246351 units

Therefore, the value of x nearest to tenth is, 1.5 units


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vodka [1.7K]

The speed for which Brian iron the shirts is given by:

R = \frac{\frac{2}{9}}{3\frac{3}{5}}

Rewriting we have:

R = \frac{\frac{2}{9}}{\frac{18}{5}}

R = \frac{10}{162}

Then, for each minute, we have the amount of ironed shirt is:

(\frac{10}{162})(1) = \frac{10}{162}

Answer:

At this rate, Brian plans 10/162 of his shirt.

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What are the coordinates of point C? *
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-2,-3

Step-by-step explanation:

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3 years ago
Emmett gathered some data to compare the monthly cost of renting a one-bedroom apartment in Dallas and Austin. The data collecte
Goryan [66]

Answer:

The correct options are;

a) The city's data has the higher median monthly apartment cost of the two cities by $155

b) The city's data had the greater variability among monthly apartment costs because the standard deviation was $49.13 more than that of the other set of data

Step-by-step explanation:

The given data for the cost of renting a one-bedroom apartment in Dallas is presented as follows;

$994, $1,322, $1,075, $1,189, $1,172, $1,465, $1,215, $930, $1,090, $1,288

Which can be arranged in increasing order and analyzed to find the interquartile range, mean and standard deviation using Microsoft Excel as follows;

$930, $994, $1,075, $1,090, $1,172, $1,189, $1,215, $1,288, $1,322, and $ 1,465

The first quartile, Q₁ = $1,054.75

The third quartile, Q₃ = $1,296.5

The interquartile range = Q₃ - Q₁ = $241.75

The median = $1,180.5

The average monthly cost = $1,174

The standard deviation of the sample = $159.9597

The given data for the cost of renting a one-bedroom apartment in Austin is presented in increasing order using Microsoft Excel as follows;

$900, $950, $1,100, $1,250, $1,296, $1,375, $1,389, $1,400, $1,450, $1,495

The interquartile range, mean and standard deviation are found using Microsoft Excel as follows;

The first quartile, Q₁ = $1,062.5

The third quartile, Q₃ = $1,412.5

The interquartile range = Q₃ - Q₁ = $1,412.5 - $1,062.5 = $350

The median = $1,335.5

The average monthly cost = $1,260.5

The standard deviation of the sample = $209.0945

The difference in the median cost of the two cities is $1,335.5 - $1,180.5 = $155

Therefore, the Austin's city data has the higher median monthly apartment cost of the two cities by $155

b) The difference in the sample standard deviation of the two cities is $209.0945 - $159.9597 = $49.13476

Therefore, the Austin city data had the greater variability among monthly apartment costs because the standard deviation was $49.13 more than that of the other set of data.

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Simplify 2/14 to 1/7

x = -1/7

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