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Lelu [443]
3 years ago
5

What's the answer and how do you do it?

Mathematics
2 answers:
Monica [59]3 years ago
7 0
The vertical asymptotes for a rational expression, occur at the values of "x" that make the denominator 0, and therefore the expression undefined.

what are those anyway?  simple, just set the denominator to 0, solve for "x", and that will spit them out.

x + 4 = 0
x = -4

there, if "x" ever becomes -4, then the fraction turns to \bf \cfrac{1}{x+4}\implies \cfrac{1}{-4+4}\implies \stackrel{und efined}{\cfrac{1}{0}}

thus, that's where the vertical asymptote is at, x = -4.
kykrilka [37]3 years ago
4 0
A vertical asymptote is when y gets higher and higher or lower and lower without stopping around a certain point. In a fraction one way this can happen is when there is a point where the denominator is 0, as when it gets close to 0 it gets bigger and bigger, and anything over 0 is undefined. Therefore the answer is A as 1/4-4 is 1/0 and an asymptote
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5, 8, II, 14 ...<br>The pattern is<br>Next 2 terms =​
QveST [7]

Answer:

the next two terms are 17, 20

Step-by-step explanation:

add 3 to each term

Example

5+3 = 8

8+3= 11

11+3= 14 etc.

4 0
3 years ago
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Given the matrices: 1 2 A= 1 -1 2 1 1 B= 3 4 Calculate AB: C11 C12 [2.1] х 1 2 3 4 C21 C22 C11 = C12 = -2 C22 - C215 DONE​
eduard

Answer:

\:c_{11}=-2,\:\:\:c_{12}=-2

\:c_{21}=5,\:\:\:c_{22}=8

Step-by-step explanation:

Given the matrices

A=\begin{pmatrix}1&-1\\ 2&1\end{pmatrix}

B=\begin{pmatrix}1&2\\ \:3&4\end{pmatrix}

Calculating AB:

\begin{pmatrix}1&-1\\ \:\:2&1\end{pmatrix}\times \:\begin{pmatrix}1&2\\ \:\:3&4\end{pmatrix}=\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}

Multiply the rows of the first matrix by the columns of the second matrix

                                   =\begin{pmatrix}1\cdot \:1+\left(-1\right)\cdot \:3&1\cdot \:2+\left(-1\right)\cdot \:4\\ 2\cdot \:1+1\cdot \:3&2\cdot \:2+1\cdot \:4\end{pmatrix}

                                   =\begin{pmatrix}-2&-2\\ 5&8\end{pmatrix}

Hence,

\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}=\begin{pmatrix}-2&-2\\ \:5&8\end{pmatrix}

Therefore,

\:c_{11}=-2,\:\:\:c_{12}=-2

\:c_{21}=5,\:\:\:c_{22}=8

5 0
3 years ago
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A belouga whale is 5 yards and 3 inches long and a gary whale is 15 yards and 5 incheslong
belka [17]

Answer:

10 yards 2 inches

Step-by-step explanation:

15 yd 5 in - 5 yd 3 in =

10 yards and 2 inches

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3 years ago
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If QR= 3x-2, RS= 2x+1, QS=6x-3, and R is between Q and S, then RS=​
rewona [7]

Answer:

RS = 5

Step-by-step explanation:

Since R is between Q and S , then

QS = QR + RS , that is

6x - 3 = 3x - 2 + 2x + 1

6x - 3 = 5x - 1 ( subtract 5x from both sides )

x - 3 = - 1 ( add 3 to both sides )

x = 2

Then

RS = 2x + 1 = 2(2) + 1 = 4 + 1 = 5

4 0
3 years ago
Choose Yes or No to tell if the expression is equal to 8 x 40.
devlian [24]
No i don’t think so
3 0
3 years ago
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