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3 years ago

Find the least 6 digit number which is a perfect square and also find its square root.

Mathematics

2 answers:

Alex17521 [72]3 years ago

6 0

It would be 100000. Square root of it is 316.227766017.

KatRina [158]3 years ago

5 0

<span>
<span>The smallest 6 digit number is 100000 We find the square root of 100000 with a calculator: = 316.227766 We take the next larger whole number 317 We square 317 317² = 100489 </span>
</span>

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What is 9713 rounded to the place value

Akimi4 [234]

It could be 10000,9800,or 9710

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3 years ago

a rectangle has a length of 11 feet and the perimeter of 38 feet. what the width in feet of the rectangle

Sati [7]

If p= 38
You need four sides to equal that
11 is length so that means two sides are 11
11+11= 22
So that means you need two more equal numbers that will finish making up the 22
38-22= 16
But two sides make up 16
16 divides by 2 is 8
So THE WIDTH IS 8

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3 years ago

Read 2 more answers

Given -8(x-3)=-32 prove x=7

AleksAgata [21]

Step-by-step explanation:

Plug x in :

-8(7-3) = -32

Distribute :

-56 - (-24) = -32

Subtract :

-32 = -32

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3 years ago

What is the solution to this equation?

Ugo [173]

Answer:

C. x = 12

Step-by-step explanation:

5(12) + 9 = 69 - 3(12) = 33

18 + 15 = 33

6 0

2 years ago

Read 2 more answers

Due to a manufacturing error, two cans of regular soda were accidentally filled with diet soda and placed into a 18-pack. Suppos

crimeas [40]

Answer:

a) There is a 1.21% probability that both contain diet soda.

b) There is a 79.21% probability that both contain diet soda.

c) $P(X = 2)$ is unusual, $P(X = 0)$ is not unusual

d) There is a 19.58% probability that exactly one is diet and exactly one is regular.

Step-by-step explanation:

There are only two possible outcomes. Either the can has diet soda, or it hasn't. So we use the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

A number of sucesses $x$ is considered unusually low if $P(X \leq x) \leq 0.05$ and unusually high if $P(X \geq x) \geq 0.05$

In this problem, we have that:

Two cans are randomly chosen, so $n = 2$

Two out of 18 cans are filled with diet coke, so $\pi = \frac{2}{18} = 0.11$

a) Determine the probability that both contain diet soda. P(both diet soda)

That is P(X = 2).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 2) = C_{2,2}(0.11)^{2}(0.89)^{0} = 0.0121$

There is a 1.21% probability that both contain diet soda.

b)Determine the probability that both contain regular soda. P(both regular)

That is P(X = 0).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 0) = C_{2,0}(0.11)^{0}(0.89)^{2} = 0.7921$

There is a 79.21% probability that both contain diet soda.

c) Would this be unusual?

We have that $P(X = 2)$ is unusual, since $P(X \geq 2) = P(X = 2) = 0.0121 \leq 0.05$

For P(X = 0), it is not unusually high nor unusually low.

d) Determine the probability that exactly one is diet and exactly one is regular. P(one diet and one regular)

That is P(X = 1).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 1) = C_{2,1}(0.11)^{1}(0.89)^{1} = 0.1958$

There is a 19.58% probability that exactly one is diet and exactly one is regular.

8 0

3 years ago