Answer:
Number of positive four-digit integers which are multiples of 5 and less than 4,000 = 600
Explanation:
Lowest four digit positive integer = 1000
Highest four digit positive integer less than 4000 = 3999
We know that multiples of 5 end with 0 or 5 in their last digit.
So, lowest four digit positive integer which is a multiple of 5 = 1000
Highest four digit positive integer less than 4000 which is a multiple of 5 = 3995.
So, the numbers goes like,
1000, 1005, 1010 .....................................................3990, 3995
These numbers are in arithmetic progression, so we have first term = 1000 and common difference = 5 and nth term(An) = 3995, we need to find n.
An = a + (n-1)d
3995 = 1000 + (n-1)x 5
(n-1) x 5 = 2995
(n-1) = 599
n = 600
So, number of positive four-digit integers which are multiples of 5 and less than 4,000 = 600
Hello!
I believe there are a total of 12 possible outcomes for this problem. Using simple math, you can just multiply 4 by 3 to get 12 possible outcomes but you can also get 12 outcomes by looking at the fact that since there are 3 plans in each of the 4 models, there are 12 ways that this could play out.
I hope this helps!
Answer:
2 ( a + 7)
Step-by-step explanation:
2a + 14
both 2a and 14 are divisible by 2
2a/a = a
14/2 = 7
2( a + 7) = 2a + 14
If my answer is incorrect, pls correct me!
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-Chetan K
Area of the sector = 1/2 * r^2 * theta where theta is the angle subtended by the arc at the center ( in radians)
In this case m < theta = 360 - 235 = 125 degrees or 2.182 radians
So, the area of shaded area = 1/2 * 20^2 * 2.182 = 436.4 in^2
Answer:
9 times. 72/8=t or 72=8t.
Explanation:
I'm afraid the answer choices are slightly mixed up, but acceptable answers would probably include 72/8=t or 72=8t. Simply put the two numbers into a fraction (72/8) to get how many times larger or smaller the thing is. In this case, it would be 9 times as many worms.
