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EastWind [94]
3 years ago
5

How do I solve this radical?

Mathematics
1 answer:
stepladder [879]3 years ago
8 0
(2√15)/ √3
= (2 × √3 × √5) ÷√3
= 2 √5
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the first term of an arthimetic sequence is 42 the rule an= an-1 +8 can 1 can be used explain how to write explict rules
Svet_ta [14]

Answer:

34 + 8n

Step-by-step explanation:

a₁ = 42

a_{n} = a_{n-1} + 8

a₂ = a₁ + 8    = 42 + 8   = 50

a₃ = a₂ + 8   = 50 + 8 = 58

a₄ = a₃ + 8 =   58 + 8  = 66

Arithmetic sequence: 42, 50 , 58 , 66, ......

a₁ = 42 ; d = 8

a_{n} = a₁ + d(n-1)

    = 42 + 8(n - 1)

    = 42 + 8n - 8

   = 34 + 8n

3 0
2 years ago
Read 2 more answers
The area of a parallelogram is 96 cm2. The height of the parallelogram is 4 cm less than the length of the base. What is the len
Valentin [98]
96/4=24 so the length of a standerd paralleegram is 24
4 0
3 years ago
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What is the measure of the secant DE?
ladessa [460]
Using the formula (AB +BC) *BC = (DE +CD) *CD

fill i n what is known:

(17 + 4) *4 = (DE +6) *6

21*4 = (DE +6)*6

84 = (DE+6)*6

84/6 = DE+6

14 = DE +6

DE = 14-6
DE = 8
4 0
3 years ago
on a piece of paper, graph this system of inequalities. Then determine which region contains the solution to the system. a pictu
slava [35]

C. Region D

Step-by-step explanation:

Just plug the equations into desmos the calculator will graph it and show you with colors where the solution is.

4 0
3 years ago
How much chromium-51 will be left after 7 months?
Makovka662 [10]

Answer:

It seems there's more information in you question that you haven't posted.

7 months = 7 * (365/12) = 213 days

The half-life of chromium 51 is 27.7 days.

After 7 months, chromium 51 will have undergone 7.69 half-lives.

To solve for the ending amount we'll use the formula:

Ending Amount = Beginning Amount / 2^n where 'n' = # of half-lives

We'll say the beginning amount =1

Ending Amount = 1 / 2^7.69

Ending Amount = 0.0048426082

Basicaly if you started with 1 gram of chromium 51, after 7 months you would have 0.0048426082 grams.

Source: https://www.1728.org/halflife.htm

Step-by-step explanation:

6 0
3 years ago
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