Step-by-step explanation:
35. 1000 m / 1 km = 10³
Move the decimal point 3 places to the right.
36. 100 cm / 1 m = 10²
Move the decimal point 2 places to the right.
37. 1 mm / 1000 μm = 10⁻³
Move the decimal point 3 places to the left.
38. 1 km / 1000 m × 1 m / 100 cm = 10⁻⁵
Move the decimal point 5 places to the left.
39. 1 Mm / 10⁶ m × 1 m / 10⁶ μm = 10⁻¹²
Move the decimal point 12 places to the left.
40. 100 cm / m × 1000 m / km = 10⁵
Move the decimal point 5 places to the right.
To solve this problem you must apply the formula for calculate the surface area of a circle, which is shown below:
SA=πir^2
where r is the radius of the circle
r=18 inches
By substituying values, you have that the surface area is:
SA=π(18 in)^2
SA=324π in^2
The answer is 324π in^2
Answer:
C) x = 8√3 ; y = 4√3
Step-by-step explanation:
In this figure, the triangle is 30°-60° right triangle.
So x/12= 2/√3, y/12 = 1/√3
2.5% of 60,000 is 1,500. So Bozeman's population will grow to 61,500 residents next year.
Question:
Which expression is equivalent to
![\frac{\sqrt{2}}{\sqrt[3]{2}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D)
Answer:
![\frac{\sqrt{2}}{\sqrt[3]{2}} =2^{\frac{1}{6}} = \sqrt[6]{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%20%3D2%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D%20%3D%20%5Csqrt%5B6%5D%7B2%7D)
Step-by-step explanation:
Given
![\frac{\sqrt{2}}{\sqrt[3]{2}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D)
Required
Simplify
From laws of indices;
![\sqrt[n]{x} =x^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%20%3Dx%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
So, the expression can be rewritten as
![\frac{\sqrt{2}}{\sqrt[3]{2}} = \frac{{2^{\frac{1}{2}}}}{2^{\frac{1}{3}}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%20%3D%20%5Cfrac%7B%7B2%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7D%7B2%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%7D)
Also, from laws of indices

So, the expression is further solved to:
![\frac{\sqrt{2}}{\sqrt[3]{2}} =2^{\frac{1}{2} - \frac{1}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%20%3D2%5E%7B%5Cfrac%7B1%7D%7B2%7D%20-%20%5Cfrac%7B1%7D%7B3%7D)
Solve exponents as fraction
![\frac{\sqrt{2}}{\sqrt[3]{2}} =2^{\frac{3-2}{6}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%20%3D2%5E%7B%5Cfrac%7B3-2%7D%7B6%7D%7D)
![\frac{\sqrt{2}}{\sqrt[3]{2}} =2^{\frac{1}{6}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%20%3D2%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D)
This can be rewritten as
![\frac{\sqrt{2}}{\sqrt[3]{2}} =2^{\frac{1}{6}} = \sqrt[6]{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%20%3D2%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D%20%3D%20%5Csqrt%5B6%5D%7B2%7D)