Question

The area of a triangular flag is 132 square centimetres. Its altitude is 2 centimetres longer than twice its base. Find the lengths of the altitude and the base.

Answer 1

Answer:

24 cm and 11 cm

Step-by-step explanation:

GIVEN: The area of a triangular flag is $132 \text{ cm}^2$. Its altitude is $2\text{ cm}$ longer than twice its base.

TO FIND: lengths of the altitude and the base.

SOLUTION:

Let the altitude and the base of flag be $a$ and $b$

According to the question

$a=2+2b$

area of triangle $=\frac{1}{2}\times base \times alltitude=\frac{1}{2}a\times b$

$\implies \frac{1}{2}(2b+2)b=132 \Rightarrow 2b^2+2b-264$

Solving equation we get

$b=11$   then $a=24$

Hence the lengths of altitude and base of triangular flag is 24 cm and 11 cm respectively.