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3 years ago

5 (-3p +7) + 5 (p -1)

Mathematics

2 answers:

RSB [31]3 years ago

4 0

5(-3p + 7) + 5(p - 1) = 0
-15p + 35 + 5p - 5 = 0
-10p + 30 = 0
-10p = -30
p = 3

gtnhenbr [62]3 years ago

3 0

Well first u gotta simplify the equation by multiplying the outside number (the 5) into the parenthesis.

Original: 5(-3p+7)
simplified: -15p+35

and then you do the same for the other part.

Original: 5(p-1)
Simplified: 5p-5

Now thats done, you now have the new equation as -15+35+5p-5

And finally you combine like terms and your final answer should be -10p+30

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Answer:

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Step-by-step explanation:

<u><em>The complete question is</em></u>

Saige's spaceship traveled 588 kilometers in 60 seconds.

Determine whether or not each spaceship trip below has the same speed as Saige's spaceship.

441km in 45s

215km in 25s

649km in 110s

we know that

The speed is equal to divide the total distance traveled by the total time

In this problem we have that

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case 1) we have

441km in 45s

Find out the speed of the spaceship trip

$\frac{441}{45}=9.8\ \frac{km}{sec}$

Compare the speed of the spaceship trip with the speed of Saiges spaceship

$9.8\ \frac{km}{sec}=9.8\ \frac{km}{sec}$

therefore

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case 2) we have

215km in 25

Find out the speed of the spaceship trip

$\frac{215}{25}=8.6\ \frac{km}{sec}$

Compare the speed of the spaceship trip with the speed of Saiges spaceship

$8.6\ \frac{km}{sec}\neq 9.8\ \frac{km}{sec}$

therefore

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case 3) we have

649km in 110s

Find out the speed of the spaceship trip

$\frac{649}{110}=5.9\ \frac{km}{sec}$

Compare the speed of the spaceship trip with the speed of Saiges spaceship

$5.9\ \frac{km}{sec}\neq 9.8\ \frac{km}{sec}$

therefore

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