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zheka24 [161]
3 years ago
12

5 (-3p +7) + 5 (p -1)

Mathematics
2 answers:
RSB [31]3 years ago
4 0
5(-3p + 7) + 5(p - 1) = 0
-15p + 35 + 5p - 5 = 0
-10p + 30 = 0
-10p = -30
p = 3
gtnhenbr [62]3 years ago
3 0
Well first u gotta simplify the equation by multiplying the outside number (the 5) into the parenthesis.

Original: 5(-3p+7)
simplified: -15p+35

and then you do the same for the other part.

Original: 5(p-1)
Simplified: 5p-5

Now thats done, you now have the new equation as -15+35+5p-5

And finally you combine like terms and your final answer should be -10p+30
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In a school, the ratio of musicians to athletes is 3 : 1. The number of musicians is how many times the number of athletes?
Flura [38]

In a school, the ratio of musicians to athletes is 3 : 1. The number of musicians is how many times the number of athletes?

Answer:

3 times as many as the athletes

Hope that helps and good luck

~May

8 0
3 years ago
Witch is a composite number A 41 B 61 C 71 D 81 pls help me
valina [46]

Answer:

D 81

Step-by-step explanation:

It is not prime. It can be divided by a number other than 1.

8 0
2 years ago
Solve for x and explain?
zhannawk [14.2K]

Answer:

x = 7

Step-by-step explanation:

When 2 secants are drawn from an external point to a circle.

The product of the external part and the entire secant of one secant is equal to the product of the external part and the entire secant of the other secant, that is

5(5 + x) = 6(6 + 4) ← distribute and simplify both sides

25 + 5x = 6 × 10

25 + 5x = 60 ( subtract 25 from both sides )

5x = 35 ( divide both sides by 5 )

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4 0
3 years ago
Hey can you please help me posted picture of question
nirvana33 [79]
(8x^2+2x+8)+(3x^3+7x+4)=
8x^2+2x+8+3x^3+7x+4
3x^3+8x^2+(2+7)x+12=
3x^3+8x^2+9x+12

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8 0
2 years ago
Read 2 more answers
Every year after a new car is
slavikrds [6]

Answer: The value of the car after 3 years is $5,333.333

And no, the relationship is not linear, is an exponential decay.

Step-by-step explanation:

We know that every year, the car loses 1/3 of its value.

So if the initial value of the car is V.

After one year, the new value of the car will be:

Value (1 year) = V - (1/3)*V = (2/3)*V

After another year, the value will be:

Value (2 years) = (2/3)*V - (1/3)*(2/3)*V = V*(2/3)^2

Ok, we already can see that this is an exponential decay.

(So no, this is not a linear relationship).

The value equation as a function of the number of years will be:

Value(N) = V*(2/3)^N

Then if the initial cost of a car is $18,000, and we want to know its value after 3 years, we need to replace V by $18,000 and N by 3 in the above equation:

Value(3) = $18,000*(2/3)^3 = $5,333.333

6 0
3 years ago
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