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arsen [322]
3 years ago
7

This is easy math!!! i just don’t know if this would be sas or sss

Mathematics
2 answers:
const2013 [10]3 years ago
8 0

Answer:

Sas

Step-by-step explanation:

stira [4]3 years ago
4 0

Answer:

SAS = side angle side

Step-by-step explanation:

Because you are comparing two sides and an angle

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Harman [31]

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Bet

Step-by-step explanation:

8 0
3 years ago
Please Help due today
g100num [7]

Answer:

the awnser should be 4.47214 because it's the approximate value of 2√5

8 0
2 years ago
Simplify; 1/x^2+5x+6 + 1/x^2+3x+2<br><br> pls I need a step by step solution urgently
ikadub [295]

Answer:

The simplest form of  \frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2}  is  \frac{2}{(x+1)(x+3)}

Step-by-step explanation:

To add two algebraic fractions do these steps

  1. Factorize each denominator
  2. Simplify each fraction to its lowest term
  3. Find the LCM of the two denominators
  4. Divide LCM by each denominator and multiply the numerators by its corresponding quotients
  5. Add the two fraction and simplify the last answer

To simplify \frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2}

Factorize each denominator

∵ The denominator of the first fraction is x² + 5x + 6

∵ x² = (x)(x)

∵ 6 = (2)(3)

∵ (2)(x) + (3)(x) = 5x ⇒ middle term

∴ x² + 5x + 6 = (x + 2)(x + 3)

∵ The denominator of the second fraction is x² + 3x + 2

∵ x² = (x)(x)

∵ 2 = (2)(1)

∵ (2)(x) + (1)(x) = 3x ⇒ middle term

∴ x² + 3x + 2 = (x + 2)(x + 1)

Find the LCM of the two denominators

∵ The denominators are (x + 2)(x + 3) and (x + 2)(x + 1)

- LCM is all the <u><em>different factors</em></u> multiplied together

∴ LCM of them is (x + 1)(x + 2)(x + 3)

- Divide LCM by each denominator

∵ (x + 1)(x + 2)(x + 3) ÷ (x + 2)(x + 3) = (x + 1)

- Multiply the numerator of the first fraction by (x + 1)

∵ (x + 1)(x + 2)(x + 3) ÷ (x + 2)(x + 1) = (x + 3)

- Multiply the numerator of the second fraction by (x + 3)

∴  \frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2} = \frac{x+1}{(x+1)(x+2)(x+3)}+\frac{x+3}{(x+1)(x+2)(x+3)}

- Add the numerators and write the answer as a single fraction

∴  \frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2} = \frac{2x+4}{(x+1)(x+2)(x+3)}

- Factorize the numerator by taking 2 as a common factor

∵ 2x + 4 = 2(x + 2)

∴  \frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2} = \frac{2(x+2)}{(x+1)(x+2)(x+3)}

- Simplify the fraction by dividing up and down by (x + 2)

∴  \frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2} = \frac{2}{(x+1)(x+3)}

The simplest form of  \frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2}  is  \frac{2}{(x+1)(x+3)}

5 0
3 years ago
Anyone help?<br><br> What is the derivative of x^2 + 2x - 4?<br><br> Thanks!
castortr0y [4]
Let's take the derivative of each term one by 1

x^2
Apply the power rule for derivatives.
2x^(2-1) = 2x
You get 2x.

2x
Apply the power rule (x^1) and the constant multiple rule.
2 * x^(1-1) = 2 * x^0 = 2
You get 2.

-4
The derivative of a constant is 0.

Put that together and you get 2x + 2

Have an awesome day! :)
4 0
3 years ago
Read 2 more answers
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