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Scrat [10]
3 years ago
13

What is the slope-intercept form of the function described by this table?

Mathematics
1 answer:
IRINA_888 [86]3 years ago
4 0

Answer:

y = 5x + 3

Step-by-step explanation:

Slope = (13 - 8)/(2-1) = 5

Equation:

y - 8 = 5(x - 1)

y - 8 = 5x - 5

y = 5x - 5 + 8

y = 5x + 3 <-----------the slope-intercept form

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Part A: Solve A = (x + 23) for x. (4 points) Part B: Determine the value of x when A = 108. (2 points) Part C: Solve -np - 90 &g
Galina-37 [17]
<span>Part A: Solve A = (x + 23) for x.

A = x + 23

=> A - 23 = x + 23 - 23

=> A - 23 = x

=> x = A - 23 <------- answer

Part B: Determine the value of x when A = 108

Replace the value of A in the expression x = A - 23

x = 108 - 23 = 75

x = 75 <------- answer

Part C: Solve -np - 90 > 30 for n.

-np - 90 > 30

=> -np + np - 90 >30 +  np

=> - 90 > 30 + np

=> -90 - 30 > 30 - 30 + np

=> -120 > np

=> np < - 120 <----- answer
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7 0
3 years ago
A piece of pizza with a diameter of 20 inches is eaten and m
JulijaS [17]

Answer:

Step-by-step explanation:

3 0
3 years ago
Please help me out thank you
Leno4ka [110]

Answer:

  1. (-0.0008)^0 =1
  2. 1291^1 =1
  3. (1/3)^0 = 1

Step-by-step explanation:

\mathrm{Apply\:exponent\:rule}:\quad \:a^0=1,\:\\\\(-0.0008)^0 = 1\\\\1291^0 =1\\\\-(-3141)^0 = -1\\\\-(\frac{5}{8} )^0 =-1\\\\0^1 = 0\\\\(\frac{1}{3} )^0 = 1\\

6 0
3 years ago
Consider F and C below. F(x, y, z) = yz i + xz j + (xy + 6z) k C is the line segment from (2, 0, −2) to (5, 4, 2) (a) Find a fun
WITCHER [35]

Answer:

Required solution (a) f(x,y,z)=xyz+3z^2+C (b) 40.

Step-by-step explanation:

Given,

F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k

(a) Let,

F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}

Then,

f_x=yz,f_y=xz,f_z=xy+6z

Integrating f_x we get,

f(x,y,z)=xyz+g(y,z)

Differentiate this with respect to y we get,

f_y=xz+g'(y,z)

compairinfg with f_y=xz of the given function we get,

g'(y,z)=0\implies g(y,z)=0+h(z)\implies g(y,z)=h(z)

Then,

f(x,y,z)=xyz+h(z)

Again differentiate with respect to z we get,

f_z=xy+h'(z)=xy+6z

on compairing we get,

h'(z)=6z\implies h(z)=3z^2+C   (By integrating h'(z))  where C is integration constant. Hence,

f(x,y,z)=xyz+3z^2+C

(b) Next, to find the itegration,

\int_C \vec{F}.dr=\int_C \nabla f. d\vec{r}=f(5,4,2)-f(2,0,-2)=(52+C)-(12+C)=40

3 0
3 years ago
25, 8, 10, 35, 5, 45, 40, 30, 20
Lera25 [3.4K]
B.) 37.5.. First you place all the numbers in order from least to greatest. Your mean is 25...and ur upper quartile because the 4 #'s fall even u add 35 and 40 and divide by 2... Which gives u upper quartile of 37.5 and lower quartile of 9. Hope this helps :)
4 0
3 years ago
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