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3 years ago

the coordinates of a pentagon ABCDE are A(-5,4),B (1,4),C(1,-1), D(-2,-5) and E(-5,-1) what is the perimeter of the pentagon

2 answers:

7 0

Perimeter is a continuous line forming the boundary of a closed geometrical figure. perimeter of a pentagon = AB+BC+CD+DE+EA (that is 5 sided figure)
so my plan is easy but effective, calculate all those distances using those coordinates with the aid of distance formular. then you add those distances algebraically .

Radda [10]3 years ago

6 0

Answer:

26 units

Step-by-step explanation:

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Fu Haifeng of China set a badminton world record with a smash of 332 kilometers per hour. A kilometer is about 58 mile.What is t

katrin [286]

Answer:

206 miles/hour

Step-by-step explanation:

1 kilometre per hour = 0.621 mile per hour

332 km/hr to miles per hour

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Approximately to the nearest whole number

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2 years ago

My friend sent me this to work on, but I’m confused on how to do it :(

marin [14]

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Step-by-step explanation:

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2 years ago

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The triangles are similar. The area of the larger triangle is 270 square centimeters. What is the area of the smaller triangle?

Vitek1552 [10]

The smaller triangle is 1/6 the size of the large one ( 5/30 = 1/

Area is squared 1/6 ^2 = 1/36

Multiply the area of the large triangle by 1/36:

270 x 1/36 = 270 /36 = 7.5

The area is 7.5 cm^2

The answer is A.

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3 years ago

Amanda has $5200 in a savings account that earns 4% annually. If the interest is not compounded, what is the value of her accoun

iren2701 [21]

The interest is simple
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3 years ago

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Help appreciated on question in image!<br> Thanks:)

Verdich [7]

Answer:

$x=-1,\:x=-7,\:x=i,\:x=-i$

Step-by-step explanation:

Considering the equation

$x^4+8x^3+8x^2+8x+7=0$

Solving

$x^4+8x^3+8x^2+8x+7$

$\mathrm{Factor\:}x^4+8x^3+8x^2+8x+7:\quad \left(x+1\right)\left(x+7\right)\left(x^2+1\right)$

$\mathrm{Use\:the\:rational\:root\:theorem}$

$a_0=7,\:\quad a_n=1$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:7,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:7}{1}$

$-\frac{1}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+1$

$=\left(x+1\right)\frac{x^4+8x^3+8x^2+8x+7}{x+1}...[A]$

Solving

$\frac{x^4+8x^3+8x^2+8x+7}{x+1}$

$=x^3+7x^2+x+7$

Putting $\frac{x^4+8x^3+8x^2+8x+7}{x+1}$ = $x^3+7x^2+x+7$ in equation [A]

So,

$\left(x+1\right)\frac{x^4+8x^3+8x^2+8x+7}{x+1}...[A]$

$=\left(x+1\right)x^3+7x^2+x+7$

$x^3+7x^2+x+7=\left(x+7\right)\left(x^2+1\right)$

So,

Equation [A] becomes

$=\left(x+1\right)\left(x+7\right)\left(x^2+1\right)$

So, the polynomial equation becomes

$\left(x+1\right)\left(x+7\right)\left(x^2+1\right)=0$

$\mathrm{Using\:the\:Zero\:Factor\:Principle:\quad \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$ $\mathrm{Solve\:}\:x+1=0:\quad x=-1$