Answer:416
Step-by-step explanation: Based on the given problem above, it requires a trigonometric solution. So here it goes:
The climb distance is:200 * Sec [ArcTan [10/200]] = 10√ 401 km
and the decent distance is:300 * Sec [ArcTan [10/300]] = 10√901 km
So add the given results above with 500 km and this will be the additional distance that plane moves through the air.
The answer would be in the unit meters.
((10√401 +10√901−500)∗1000)=416 meters
Hope this is the answer that you are looking for.
Known :
f(x) = -3x - 5
g(x) = 4x - 2
Asked :
(f+g)(x) = ...?
Answer :
(f+g)(x) = (-3x - 5) + (4x - 2)
= (-3x + 4x) + (-5 - 2)
= x + (-7)
= <u>x </u><u>-</u><u> </u><u>7</u>
So, the value of (f+g)(x) is x - 7
<em>Hope </em><em>it </em><em>helpful </em><em>and </em><em>useful </em><em>:</em><em>)</em>
Answer:
559,999
Step-by-step explanation:
Answer:
m<R = m<T = 80.5 deg
Step-by-step explanation:
3)
Since WXYZ is a square, <WXZ is formed with a diagonal of the square and has measure 45 deg.
m<WXZ = 8x - 19 = 45
8x - 19 = 45
8x = 64
x = 8
4)
Draw the kite. Make sure that segments QR and RS are not congruent. Fill in the given angle measures. Angles R and T are congruent opposite angles.
The sum of the measures of the interior angles of a convex, n-sided polygon is
180(n 2).
A kite is a quadrilateral, so n = 4.
180(4 - 2) = 180(2) = 360
The sum of the measures of the interior angles of a kite is 360 deg.
m<Q + m<R + m<S + m<T = 360
75 + m<R + 124 + m<T = 360
m<R + m<T + 199 = 360
m<R + m<T = 161
m<R = m<T, so we substitute m<T with m<R.
m<R + m<R = 161
2m<R = 161
m<R = 80.5
m<R = m<T = 80.5 deg
