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Dennis_Churaev [7]
4 years ago
15

If the space station is 190 m in diameter, what angular velocity would produce an "artificial gravity" of 9.80 m/s2 at the rim?

Give your answer in rad/s.
Physics
1 answer:
ozzi4 years ago
6 0

Answer:

The angular velocity produced is 0.321 rad/s.

Explanation:

Given :

Diameter of space station , D = 190 m.

Therefore, radius , R=\dfrac{D}{2}=\dfrac{190}{2}=95\ m.

Also, acceleration , a=9.8\ m/s^2.

We know, angular velocity , \omega=\sqrt \dfrac{a}{R}.

Putting value of g and R in above equation.

We get ,

\omega=\sqrt \dfrac{9.8\ m/s^2}{95\ m}

\omega=0.321\ rad/s.

Hence, this is the required solution.

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Answer:

I think its B

Explanation:

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A wheel is rotating about a fixed axis with constant angular acceleration 3 rad/s². At different moments, its angular speed is -
meriva

b and e are the largest and equal in magnitude. w*2R = (2)(2)R = 4R

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c is zero. wR = v = 0; Angular acceleration is zero.

<h3>What is angular acceleration?</h3>
  • The temporal rate at which angular velocity changes is known as angular acceleration. The standard unit of measurement is radians per second per second. Therefore, = d d t. Rotational acceleration is another name for angular acceleration.
  • Angular velocity divided by acceleration time can be used to define angular acceleration. (t). As an alternative, use pi times the drive speed (n) divided by the acceleration time (t) times 30. Radians per second squared (Rad/sec2) is the standard SI unit for rotational acceleration resulting from this equation.
  • To calculate angular velocity, we can use one of three formulas. The definition itself provides the first. Theta = position angle, t = time, and w = angular velocity, where w = angular velocity, theta = position angle, and t = time. Angular velocity is the rate of change of an object's position angle with respect to time.
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If two items are equal, show them as equal in your ranking. If a quantity is equal to zero, show that fact in your ranking:

b and e are the largest and equal in magnitude. w*2R = (2)(2)R = 4R

A and d are next. aR = (3rad/s2)R = 3R

c is zero. wR = v = 0; Angular acceleration is zero.

To learn more about angular acceleration, refer to:

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8 0
2 years ago
A 5 kg block is pulled across a table by a horizontal force of 40 N with a frictional force of 8 N opposing the motion. Calculat
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Answer:

a = 6.4 [m/s²]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration. In this way, we have the following equation.

∑F = m*a

where:

∑F = sum of forces (horizontal force = 40 [N] and friction force = 8 [N])

m = mass of the block = 5 [kg]

a = acceleration [m/s²]

Now replacing:

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Note: the sign of the friction force is negative since this force is acting against the movement of the block.

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An escalator carries you from one level to the next in an airport terminal. the upper level is 4.3 m above the lower level, and
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