Need some help plsss!

zaharov [31]

I can answer the first question: Water rises because of the sun's heat and turns into water vapor. After that, it gathers up and forms a cloud. When the cloud is filled enough with vapor, precipitation occurs.

3 0

4 years ago

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Two a.c V1=100sin(wt) and V2 = 150cos(wt) are fed into one circuit, determine the combined output of the two as a single a.c

Dominik [7]

Answer:

Explanation:

V = 100sin(ωt) + 150cos(ωt)

let x = ωt

V = 100sin(x) + 150cos(x)

a maximum or minimum will occur when the derivative is zero

V' = 100cos(x) - 150sin(x)

0 = 100cos(x) - 150sin(x)

100cos(x) = 150sin(x)

100/150 = sin(x)/cos(x)

0.6667 = tan(x)

x = 0.588 rad

V = 100sin(0.588) + 150cos(0.588)

V = 180.27756

as the maximum will not occur until ωt = 0.588 radians, for a cosine function we subtract that amount as a phase angle φ

V = 180.3 cos(ωt - 0.588)

or as a sine function, the phase angle lags the cosine by a difference of π/2

V = 180.3sin(ωt - (0.588 - π/2)

V = 180.3sin(ωt + 0.983)

7 0

3 years ago

g is incident on 3 successive sheets of polarizing material. The transmission axis of the first sheet is vertical. The transmiss

murzikaleks [220]

Answer:

The intensity of light passing from the third polarizer is 3Io/16.

Explanation:

The law of Malus is given by

$I=I_o cos^2\theta$

Let the incident intensity of light is Io.

The intensity of light passing from the first polarizer is

$I' = \frac{I_o}{2}$

The intensity of light passing from the second polarizer is

$I''=\frac{I_o}{2}\times cos^230 =\frac{3I_o}{8}$

The intensity of light passing from the third polarizer is

$I''' = \frac{3I_o}{8}\times cos^2 60\\\\\\I''' = \frac{3I_o}{16}$

6 0

3 years ago

A car (mass 1200 kg, speed 100 km/h) and a truck (mass 2800 kg, speed 50 km/h) are moving in the same direction along a highway.

Sloan [31]

Answer:

Speed of the wreck after the collision is 65 km/h

Explanation:

When a car hits truck and sticks together, the collision would be totally inelastic. Since the both the vehicles locked together, they have the same final velocity.

Mass of car $m_{1}=1200 kg$

Mass of truck $m_{2}=2800 kg$

Initial speed of the car $u_{1}=100 km /h$

Initial speed of the truck $u_{2}=50 km /h$

The final velocity of the wreck will be

$m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}$

since final speed are same, $v_{1}=v_{2}=v$

$m_{1}u_{1}+m_{2}u_{2}=(m_{1}+m_{2})v$

$1200\times 100 +2800 \times 50 =(1200+2800)v\\v=\frac{260000}{4000} \\v=65 km/h$

5 0

3 years ago

How does Earth's rotation affect our view of stars

bonufazy [111]

Due to rotation of Earth on each day, our East & west gets change in every half day, and comes in it's initial state after a day. So, Stars which are in east relative to a stationary object in the Universe, will be in west relative to Earth after some time, and it changes our view of stars

Hope this helps!

4 0

3 years ago