Question

NEED HELP ASAP!!!!!!!!!!!

Answer 1

Answer:

Step-by-step explanation:

Let the no of cars be x and no of buses be y.

x + y = 60 -> y = 60 - x

6x + 30y = 600

with the available equations let us calculate the values of x and y.

6x + 30 * (60-x) = 600

6x + 1800 - 30x = 600

24x = 1200

x cars = 50

y buses = 10

maximum profit = 50 * 2.5 + 10 * 7.5 = $200