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Svetradugi [14.3K]
2 years ago
9

A researcher wishes to estimate the proportion of X-ray machines that malfunction. A random 275 sample of machines is taken, and

228 of the machines in the sample malfunction.
Based upon this, compute a 95% confidence interval for the proportion of all X-ray machines that malfunction. Then complete the table below.
Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places.
What is the lower limit of the 95% confidence interval?
What is the upper limit of the 95% confidence interval?
Mathematics
1 answer:
Dominik [7]2 years ago
4 0

Answer:

Following are the solution to the given question:

Step-by-step explanation:

95\% Confidence Interval for both the percentage of all x-ray machines

p = the machinery's share is not working:

= \frac{228}{275}\\\\ = 0.829

\text{Margin of Error} = Z_{(\frac{\alpha}{2})} \times \sqrt{( p \times (1-p)}{n})

                         = 1.96 \times \sqrt{(0.829 \times \frac{0.171}{275})} \\\\= 1.96 \times 0.023 \\\\= 0.045

Lower 95\% Confidence interval = p - error margin = 0.829 - 0.045 = 0.784

Upper 95\% Confidence Interval = p + error margin= 0.829 + 0.045 = 0.874

So, 95\% Confidence Interval = ( 0.78 , 0.87 )

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According to company records, 128 of 460 employees purchase health insurance through the company. The chief human resources offi
Doss [256]

Answer:

\dfrac{128}{460}\times 100 \approx \bold{27.83\%}

Step-by-step explanation:

Given that:

Number of employees who purchased health insurance through the company = 128

Total number of employees = 460

To find:

Expression to find out the percentage of employees that purchase health insurance through the company ?

Solution:

Percentage of employees that purchase health insurance through the company:

\dfrac{\text{Number of employees that purchase health insurance through the company}}{\text{Total number of employees}}\times 100

= \dfrac{128}{460}\times 100 \approx \bold{27.83\%}

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Felix's parents opened a savings
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The money in the Felix's account will be $6798 when he is 21.

<u>Step-by-step explanation:</u>

It is given that,

  • The amount deposited is $2000.
  • The account earns 6%  compound interest.
  • It is compounded  annually for 21 years.

<u>To find the money in Felix's account after 21 years :</u>

The formula used here is,

⇒ A = P(1+r/n)^{nt}

where A is the amount after 21 years.

  • P is the initial amount deposited ⇒ P = 2000
  • r is the rate ⇒ r = 0.06
  • n is the number of times interest is compounded per year⇒ n = 1
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Therefore, The money in the Felix's account will be $6798 when he is 21.

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