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andrezito [222]
3 years ago
6

191 rounded to nearest ten

Mathematics
2 answers:
Dennis_Churaev [7]3 years ago
8 0
The answer to 191 rounded to nearest ten is 190
jasenka [17]3 years ago
3 0
200 is the answer to your question

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Please Help :)<br> What is the distance between the points in the image below?
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Answer:

5?

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
A very large batch of parts (assume a normal distrbution0 from a manufacturer has a mean weight = 43g and a standard deviation =
AVprozaik [17]

Answer:

5.44% probability that exactly 8 of the 16 parts you selected will have weights exceeding 45g

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Percentage of parts with weights exceeding 45g?

1 subtracted by the pvalue of Z when X = 45. So

We have \mu = 43, \sigma = 4

Z = \frac{X - \mu}{\sigma}

Z = \frac{45 - 43}{4}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915

1 - 0.6915 = 0.3075

If you slect 16 parts at random form that batch, what is the probability that exactly 8 of the 16 parts you selected will have weights exceeding 45g?

This is P(X = 8) when n = 16, p = 0.3075. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{16,8}.(0.3075)^{8}.(0.6915)^{8} = 0.0544

5.44% probability that exactly 8 of the 16 parts you selected will have weights exceeding 45g

4 0
3 years ago
When making bread from scratch, the recipe calls for 4 /5 cup of water. If you need to make a smaller portion of the recipe, how
lisabon 2012 [21]

\frac{1}{16}  \times  \frac{4}{5}  =  \frac{4}{80}  =  \frac{1}{20}
You need 1/20 cup of water.
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So first you  have the parralelogram right then you put the triangle on the other side to make it a rectangle. Then you multiply 4 times 10 is your answer  so B



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