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3 years ago

8

Single-replacement and double-displacement reactions are given below. use the activity series to find out whether a reaction wou

ld occur and identify the products of such reactions.

1 answer:

konstantin123 [22]3 years ago

4 0

Good luck!!! j knkw this jsnt help but i know u can do jtSh good luck

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a radioisotope has a half life of three hours how much of a 120g sample remains after 9 hours. what will the g amount be after 3

aksik [14]

$\huge\boxed{♔︎Answer♔︎}$

60g after 3 hours, 30g after 6 hours and 15g after 9 hours

Explanation:

Weight of the radioactive sample = 120g

half life time period = 3 hours

(a) The weight of sample after 3 hours

$\textsf{ No. of half lives} = \sf \cancel\frac{3}{3} = 1$

The fraction of sample left

$\sf { \frac{1}{2} }^{1} = \frac{1}{2}$

Mass of the sample left

$\sf \frac{1}{2} \times 120 = \cancel\frac{120}{2} = 60g$

<u>6</u><u>0</u><u>g</u><u> </u><u>of</u><u> </u><u>sample</u><u> </u><u>is</u><u> </u><u>left</u><u> </u><u>after</u><u> </u><u>3</u><u> </u><u>hours</u>

(b) The weight of sample after 6 hours

$\textsf{ No. of half lives} = \sf \cancel\frac{6}{3} = 2$

The fraction of the sample left

$\sf { \frac{1}{2} }^{2} = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4}$

Mass of the sample left

$\sf \frac{1}{4} \times 120 = \cancel\frac{120}{4} = 30g$

<u>3</u><u>0</u><u>g</u><u> </u><u>of</u><u> </u><u>sample</u><u> </u><u>is</u><u> </u><u>left</u><u> </u><u>after</u><u> </u><u>6</u><u> </u><u>hours</u>

(c) The weight of sample after 9 hours

$\textsf {No. of half lives} = \sf \cancel\frac{9}{3} = 3$

The fraction of sample left

$\sf { \frac{1}{2} }^{3} = \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \frac{1}{8}$

Mass of sample left

$\sf \frac{1}{8} \times 120 = \cancel \frac{120}{8} = 15g$

<u>1</u><u>5</u><u>g</u><u> </u><u>of</u><u> </u><u>sample</u><u> </u><u>is</u><u> </u><u>left</u><u> </u><u>after</u><u> </u><u>9</u><u> </u><u>hours</u><u>.</u>

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2 years ago

Which combination of elements below will bond ionically and in the same ratio as lithium when it bonds to sulfur?

Xelga [282]

<span>B) sodium and oxygen </span>

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3 years ago

Read 2 more answers

The relationship between moles and volume, when pressure and temperature of a gas are held constant, is: V/n =

Dvinal [7]

Answer:

If the moles of gas are tripled, the volume must also triple.

Explanation:

According to Avogadro law,

Equal volume of all the gases at same temperature and pressure have equal number of molecules.

The number of moles and volume are directly related to each other. By increasing the number of moles volume also goes to increase with same ratio.

When number of moles decreases the volume also goes to decrease at constant temperature and pressure.

Mathematical expression:

V ∝ n

V = Kn

V/n = k

When volume is changed from V₁ to V₂ by changing the number of moles from n₁ to n₂. Then expression will be,

V₁/n₁ = V₂/n₂

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3 years ago

3. 78 mL of 2.5 M phosphoric acid is neutralized with 500 mL of potassium hydroxide. What is the

xenn [34]

Hence, concentration of base is 1.17 M

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3 years ago

In the fall, how does the high pressure area<br> affect the hurricane?

tangare [24]

Answer:

Hurricanes occur when ocean water warms during the spring, summer and early fall.

Explanation:

Warm air just above the water’s surface rises. The rising warm air creates a reduction in pressure at the surface, what meteorologists call a low-pressure area. Because nearby air is at a higher pressure, it will flow into the low-pressure zone.

https://www.sidmartinbio.org/how-does-a-high-pressure-system-affect-a-hurricane/

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3 years ago